Daik 6.6 2l651e

T1 m t2 w

t1 w

T2 m m = 7000 lb/hr aniline ; w= 10000lb/hr toluene T1=100F ; t1 = 185F T2=150F ; t2 = ? Materials = 2-by 1-in IPS ; 15 ft hairpin ∆Pallow = 10 Psi ; Rdallowable = 0,005 aniline = 0,509Btu/lb F ; toluene = 0,47 Btu/lb F (asumsi konstan dari range 185F ke t2) 1. Heat balance w x toluenex(t2-t1) = -m x anilinex(T2-T1) 10000 x 0,47 x (t2-185) = -7000 x 0,509 x (150-100) t2 = 147,096 F 2. Calculating LMTD LMTD =

( t 2−T 1 ) −(t 1−T 2) t 2−T 1 ln ⁡[ ] t 1−T 2

= 40,749 F 3. Checking viscosity from caloric temperature 

tavg =

t 1+ t 2 =166,048 F 2

µtoluene= 0,34

[ 

µtoluene µw

Tavg =

]

;

= 0,979 (arithmetic mean can be used, because µ ≤ 2

T 1+ T 2 2

= 125 F

µtaniline = 1,95

[

µ aniline µw

µw=0,395

0,14

;

µw = 0,56

0,14

]

= 1,191

Value of ho at average temperature G=

7000 2 0,014 = 500000 lb/hr ft