Introduction To Fundamental Concepts Of Chemistry For Class Xi 6hl5s

Introduction to Fundamental Concepts of Chemistry Atom It is the smallest particle of an element which can exist with all the properties of its own element but it cannot exist in atmosphere alone.

Molecule When two or more than two atoms are combined with each other a molecule is formed. It can exist freely in nature.

Formula Weight It is the sum of the weights of the atoms present in the formula of a substance.

Molecular Weight It is the sum of the atomic masses of all the atoms present in a molecule.

Chemistry It is a branch of science which deals with the properties, composition and the structure of matter.

Empirical Formula Definition It is the simplest formula of a chemical compound which represents the element present of the compound and also represent the simplest ratio between the elements of the compound. Examples The empirical formula of benzene is "CH". It indicates that the benzene molecule is composed of two elements carbon and hydrogen and the ratio between these two elements is 1:1. The empirical formula of glucose is "CH2O". This formula represents that glucose molecule is composed of three elements carbon, hydrogen and oxygen. The ratio between carbon and oxygen is equal but hydrogen is double.

Determination of Empirical Formula To determine the empirical formula of a compound following steps are required. 1. To detect the elements present in the compound. 2. To determine the masses of each element. 3. To calculate the percentage of each element. 4. Determination of mole composition of each element. 5. Determination of simplest ratio between the element of the compound.

Illustrated Example of Empirical Formula Consider an unknown compound whose empirical formula is to be determined is given to us. Now we will use the above five steps in order to calculate the empirical formula. Step I - Determination of the Elements By performing test it is found that the compound contains magnesium and oxygen elements. Step II - Determination of the Masses Masses of the elements are experimentally determined which are given below. Mass of Mg = 2.4 gm Mass of Oxygen = 1.6 gm Step III - Estimation of the Percentage The percentage of an element may be determined by using the formula. % of element = Mass of element / Mass of compound x 100 In the given compound two elements are present which are magnesium and oxygen, therefore mass of compound is equal to the sum of the mass of magnesium and mass of oxygen. Mass of compound = 2.4 + 1.6 = 4.0 gm % Mg = Mass of Mg / Mass of Compound x 100 = 2.4 / 4.0 x 100 = 60% % O = Mass of Oxygen / Mass of Compound x 100 = 1.6 / 4.0 x 100 = 40% Step IV - Determination of Mole Composition Mole composition of the elements is obtained by dividing percentage of each element with its atomic mass. Mole ratio of Mg = Percentage of Mg / Atomic Mass of Mg = 60 / 24 = 2.5 Mole ratio of Mg = Percentage of Oxygen / Atomic Mass of Oxygen = 40 / 16 = 2.5

Step V - Determination of Simplest Ratio To obtain the simplest ratio of the atoms the quotients obtained in the step IV are divided by the smallest quotients. Mg = 2.5 / 2.5 = 1 O = 2.5 / 2.5 = 1 Thus the empirical formula of the compound is MgO Note If the number obtained in the simplest ratio is not a whole number then multiply this number with a smallest number such that it becomes a whole number maintain their proportion.

Molecular Formula Definition The formula which shows the actual number of atoms of each element present in a molecule is called molecular formula. OR It is a formula which represents the element ratio between the elements and actual number of atoms of each type of elements present per molecule of the compound. Examples The molecular formula of benzene is "C6H6". It indicates that 1. Benzene molecule is composed of two elements carbon and hydrogen. 2. The ratio between carbon and hydrogen is 1:1. 3. The number of atoms present per molecule of benzene are 6 carbon and 6 hydrogen atoms. The molecular formula of glucose is "C6H12O6". The formula represents that 1. Glucose molecule is composed of three elements carbon, hydrogen and oxygen. 2. The ratio between the atoms of carbon, hydrogen and oxygen is 1:2:1. 3. The number of atoms present per molecule of glucose are 6 carbon atoms. 12 hydrogen atoms and 6 oxygen atoms.

Determination of Molecular Formula The molecular formula of a compound is an integral multiple of its empirical formula. Molecular formula = (Empirical formula)n Where n is a digit = 1, 2, 3 etc. Hence the first step in the determination of molecular formula is to calculate its empirical formula by using the procedure as explained in empirical formula. After that the next step is to calculate the value of n n = Molecular Mass / Empirical Formula Mass Example The empirical formula of a compound is CH2O and its molecular mass is 180. To calculate the molecular formula of the compound first of all we will calculate its empirical formula mass

Empirical formula mass of CH2O = 12 + 1 x 2 + 16 = 30 n = Molecular Mass / Empirical Formula Mass = 180 / 30 =6 Molecular formula = (Empirical formula)n = (CH2O)6 = C6H12O6

Molecular Mass Definition The sum of masses of the atoms present in a molecule is called as molecular mass. OR It is the comparison that how mach a molecule of a substance is heavier than 1/12th weight or mass of carbon atom. Example The molecular mass of CO2 may be calculated as Molecular mass of CO2 = Mass of Carbon + 2 (Mass of Oxygen) = 12 + 2 x 16 = 44 a.m.u Molecular mass of H2O = (Mass of Hydrogen) x 2 + Mass of Oxygen = 1 x 2 + 16 = 18 a.m.u Molecular mass of HCl = Mass of Hydrogen + Mass of Chlorine = 1 + 35.5 = 36.5 a.m.u

Gram Molecular Mass Definition The molecular mass of a compound expressed in gram is called gram molecular mass or mole. Examples 1. The molecular mass of H2O is 18. If we take 18 gm H2O then it is called 1 gm molecular mass of H2O or 1 mole of water. 2. The molecular mass of HCl is 36.5. If we take 36.5 gm of HCl then it is called as 1 gm molecular mass of HCl or 1 mole of HCl.

Mole Definition It is defined as atomic mass of an element, molecular mass of a compound or formula mass of a substance expressed in grams is called as mole.

OR The amount of a substance that contains as many number of particles (atoms, molecules or ions) as there are atoms contained in 12 gm of pure carbon. Examples 1. The atomic mass of hydrogen is one. If we take 1 gm of hydrogen, it is equal to one mole of hydrogen. 2. The atomic mass of Na is 23 if we take 23 gm of Na then it is equal to one mole of Na. 3. The atomic mass of sulphur is 32. When we take 32 gm of sulphur then it is called one mole of sulphur. From these examples we can say that atomic mass of an element expressed in grams is called mole. Similarly molecular masses expressed in grams is also known as mole e.g. The molecular mass of CO2 is 44. If we take 44 gm of CO2 it is called one mole of CO2 or the molecular mass of H2O is 18. If we take 18 gm of H2O it is called one mole of H2O. When atomic mass of an element expressed in grams it is called gram atom While The molecular mass of a compound expressed in grams is called gram molecule. According to the definition of mole. One gram atom contain 6.02 x 10(23) atoms While One gram molecule contain 6.02 x 10(23) molecules.

Avagadro's Number An Italian scientist, Avagadro's calculated that the number of particles (atoms, molecules) in one mole of a substance are always equal to 6.02 x 10(23). This number is known as Avogadro's number and represented as N(A). Example 1 gm mole of Na contain 6.02 x 10(23) atoms of Na. 1 gm mole of Sulphur = 6.02 x 10(23) atoms of Sulphur. 1 gm mole of H2SO4 = 6.02 x 10(23) molecules H2SO4 1 gm mole of H2O = 6.02 x 10(23) molecules of H2O On the basis of Avogadro's Number "mole" is also defined as Mass of 6.02 x 10(23) molecules, atoms or ions in gram is called mole. Determination Of The Number Of Atoms Or Molecules In The Given Mass Of A Substance Example 1 Calculate the number of atoms in 9.2 gm of Na. Solution Atomic mass of Na = 23 a.m.u If we take 23 gm of Na, it is equal to 1 mole. 23 gm of Na contain 6.02 x 10(23) atoms

1 gm of Na contain 6.02 x 10(23) / 23 atoms 9.2 gm of Na contain 9.2 x 6.02 x 10(23) /23 = 2.408 x 10(23) atoms of Na Determination Of The Mass Of Given Number Of Atoms Or Molecules Of A Substance Example 2 Calculate the mass in grams of 3.01 x 10(23) molecules of glucose. Solution Molecular mass of glucose = 180 a.m.u So when we take 180 gm of glucose it is equal to one mole So, 6.02 x 10(23) molecules of glucose = 180 gm 1 molecule of glucose = 180 / 6.02 x 10(23) gm 3.01 x 10(23) molecules of glucose = 3.01 x 10(23) x 180 / 6.02 x 10(23) = 90 gm

Stoichiometry (Calculation Based On Chemical Equations) Definition The study of relationship between the amount of reactant and the products in chemical reactions as given by chemical equations is called stoichiometry. In this study we always use a balanced chemical equation because a balanced chemical equation tells us the exact mass ratio of the reactants and products in the chemical reaction. There are three relationships involved for the stoichiometric calculations from the balanced chemical equations which are 1. Mass - Mass Relationship 2. Mass - Volume Relationship 3. Volume - Volume Relationship Mass - Mass Relationship In this relationship we can determine the unknown mass of a reactant or product from a given mass of teh substance involved in the chemical reaction by using a balanced chemical equation. Example Calculate the mass of CO2 that can be obtained by heating 50 gm of limestone. Solution Step I - Write a Balanced Equation CaCO3 ----> CaO + CO2 Step II - Write Down The Molecular Masses And Moles Of Reactant & Product CaCO3 ----> CaO + CO2

Method I - MOLE METHOD Number of moles of 50 gm of CaCO3 = 50 / 100 = 0.5 mole According to equation 1 mole of CaCO3 gives 1 mole of CO2 0.5 mole of CaCO3 will give 0.5 mole of CO2 Mass of CO2 = Moles x Molecular Mass = 0.5 x 44 = 22 gm Method II - FACTOR METHOD From equation we may write as 100 gm of CaCO3 gives 44 gm of CO2 1 gm of CaCO3 will give 44/100 gm of CO2 50 gm of CaCO3 will give 50 x 44 / 100 gm of CO2 = 22 gm of CO2 Mass - Volume Relationship The major quantities of gases can be expressed in of volume as well as masses. According to Avogardro One gm mole of any gas always occupies 22.4 dm3 volume at S.T.P. So this law is applied in mass-volume relationship. This relationship is useful in determining the unknown mass or volume of reactant or product by using a given mass or volume of some substance in a chemical reaction. Example Calculate the volume of CO2 gas produced at S.T.P by combustion of 20 gm of CH4. Solution Step I - Write a Balanced Equation CH4 + 2 O2 ----> CO2 + 2 H2O Step II - Write Down The Molecular Masses And Moles Of Reactant & Product CH4 + 2 O2 ----> CO2 + 2 H2O Method I - MOLE METHOD Convert the given mass of CH4 in moles Number of moles of CH4 = Given Mass of CH4 / Molar Mass of CH4 From Equation 1 mole of CH4 gives 1 moles of CO2 1.25 mole of CH4 will give 1.25 mole of CO2 No. of moles of CO2 obtained = 1.25 But 1 mole of CO2 at S.T.P occupies 22.4 dm3 1.25 mole of CO2 at S.T.P occupies 22.4 x 1.25 = 28 dm3 Method II - FACTOR METHOD Molecular mass of CH4 = 16

Molecular mass of CO2 = 44 According to the equation 16 gm of CH4 gives 44 gm of CO2 1 gm of CH4 will give 44/16 gm of CO2 20 gm of CH4 will give 20 x 44/16 gm of CO2 = 55 gm of CO2 44 gm of CO2 at S.T.P occupy a volume 22.4 dm3 1 gm of CO2 at S.T.P occupy a volume 22.4/44 dm3 55 gm of CO2 at S.T.P occupy a volume 55 x 22.4/44 = 28 dm3 Volume - Volume Relationship This relationship determine the unknown volumes of reactants or products from a known volume of other gas. This relationship is based on Gay-Lussac's law of combining volume which states that gases react in the ratio of small whole number by volume under similar conditions of temperature & pressure. Consider this equation CH4 + 2 O2 ----> CO2 + 2 H2O In this reaction one volume of CH4 gas reacts with two volumes of oxygen gas to give one volume of CO2 and two volumes of H2O Examples What volume of O2 at S.T.P is required to burn 500 litres (dm3) of C2H4 (ethylene)? Solution Step I - Write a Balanced Equation C2H4 + 3 O2 ----> 2 CO2 + 2 H2O Step II - Write Down The Moles And Volume Of Reactant & Product C2H4 + 3 O2 ----> 2 CO2 + 2 H2O According to Equation 1 dm3 of C2H4 requires 3 dm3 of O2 500 dm3 of C2H4 requires 3 x 500 dm3 of O2 = 1500 dm3 of O2

Limiting Reactant In stoichiometry when more than one reactant is involved in a chemical reaction, it is not so simple to get actual result of the stoichiometric problem by making relationship between any one of the reactant and product, which are involved in the chemical reaction. As we know that when any one of the reactant is completely used or consumed the reaction is stopped no matter the other reactants are present in very large quantity. This reactant which is totally consumed during the chemical reaction due to which the reaction is stopped is called limiting reactant. Limiting reactant help us in calculating the actual amount of product formed during the chemical

reaction. To understand the concept the limiting reactant consider the following calculation. Problem We are provided 50 gm of H2 and 50 gm of N2. Calculate how many gm of NH3 will be formed when the reaction is irreversible. The equation for the reaction is as follows. N2 + 3 H2 ----> 2 NH3 Solution In this problem moles of N2 and H2 are as follows Moles of N2 = Mass of N2 / Mol. Mass of N2 = 50 / 28 = 1.79 Moles of H2 = Mass of H2 / Mol. Mass of H2 = 50 / 2 = 25 So, the provided moles for the reaction are nitrogen = 1.79 moles and hydrogen = 25 moles But in the equation of the process 1 mole of nitrogen require 3 mole of hydrogen. Therefore the provided moles of nitrogen i.e. 1.79 require 1.79 x 3 moles of hydrogen i.e. 5.37 moles although 25 moles of H2 are provided but when nitrogen is consumed the reaction will be stopped and the remaining hydrogen is useless for the reaction so in this problem N2 is a limiting reactant by which we can calculate the actual amount of product formed during the reaction. N2 + 3 H2 ----> 2 NH3 1 mole of N2 gives 2 moles of NH3 1.79 mole of N2 gives 2 x 1.79 moles of NH3 = 3.58 moles of NH3 Mass of NH3 = Moles of NH3 x Mol. Mass = 3.58 x 17 = 60.86 gm of NH3

Three States Of Matter Matter It is defined as any thing which has mass and occupies space is called matter. Matter is composed of small and tiny particles called Atoms or molecules. It exist in three different states which are gaseous, liquid & solid.

Properties of Gas

1. It has no definite shape. 2. It has no definite volume, so it can be compressed or expanded. 3. A gas may diffuse with the other gas. 4. The molecules of a gas are in continuous motion.

Properties of Liquids 1. A liquid has no definite shape. 2. It has a fixed volume. 3. The diffusion of a liquid into the other liquid is possible if both of the liquids are polar or nonpolar. 4. It can be compressed to a negligible.

Properties of Solids 1. A solid has a definite shape. 2. It has a fixed volume. 3. The rate of diffusion of solid with each other is very slow. 4. It cannot be compressed easily.

Kinetic Theory of Gases It was an idea of some scientist like Maxwell & Bolzmann that the properties of gases are due to their molecular motion. This motion of the molecules is related with the kinetic energy, so the postulates give by the scientist about the behaviour of gases are collectively known as kinetic molecular theory of gases. The postulates of kinetic molecular theory are as follows. 1. All gases consists of very large number of tiny particles called molecules. 2. These molecules are widely separated from each other and are so small that they are invisible. 3. The size of the molecules is very small as compared to the distance between them. 4. There is no attractive or repulsive force between molecules so they can move freely. 5. The molecules are very hard and perfectly elastic so when they collide no loss of energy takes place. 6. The gas molecules are in continuous motion they move in a straight path until they collide. The distance between two continuous collision is called Mean Free Path. 7. During their motion these molecules are collided with one another and with the walls of the container. 8. The collision of the molecules are perfectly elastic. When molecules collide they rebound with perfect elasticity and without loss or gain of energy. 9. The pressure of the gas is the result of collision of molecules on the walls of the container. 10. The average kinetic energy of gas molecules depends upon the absolute temperature. At any given temperature the molecules of all gases have the same average kinetic energy (1/2 mv2).

Kinetic Theory of Liquids

This theory is bases on the following assumptions. 1. The particles of a liquid are very close to each other due to which a liquid has fixed volume. 2. The particles in a liquid are free to move so they have no definite shape. 3. During the motion these molecules collides with each other and with the walls of the container. 4. These molecules possess kinetic which is directly proportional to its absolute temperature.

Kinetic Theory of Solids The assumptions of kinetic theory for solids are as follows. 1. The particles in a solid are very closely packed due to strong attractive forces between the molecules. 2. These molecules are present at a fixed position and are unable to move. 3. They have definite shape because the particles are arranged in a fixed pattern. 4. They possess only vibrational energy.

Mean Free Path The distance which a molecule of a gas travels before its collision with the other molecule is called free path. This distance between the collision of the molecules changes constantly so the average distance which a molecule travels before its collision is called mean free path.

Boyle's Law A relationship of volume with external pressure was given by Boyle's in the form of law. This law is known as Boyle's Law which states, For a given mass of a gas the volume of the gas is inversely proportional to its pressure provided the temperature is kept constant. Mathematically it may be written as V∞1/P Or V = K / P Or PV = K On the bases of the relation, Boyle's law can also be stated as The product of the pressure and volume of a given mass of a gas is always constant at constant temperature. Explanation Consider for a given mass a gas having volume V1 at pressure P1, so according to Boyle's Law we may write as P1V1 = K1 (constant) If the pressure of the above system is changed from P1 to P2 then the volume of the gas will also change from V1 to V2. For this new condition of the gas we can write as, P2V2 = K2 (constant) But for the same mass of the gas. K1 = K2

P1V1 = P2V2 This equation is known as Boyle's Equation.

Charle's Law We know that everything expand on heating and contract cooling. This change in volume is small in liquids and solids but gases exhibit enormous changes due to the presence of large intermolecular spaces. Change of volume of a gas with the change of temperature at constant pressure was studied by Charles and was given in the form of a law. which states, Statement For a given mass of a gas the volume of the gas is directly proportional to its absolute temperature provided the pressure is kept constant. Mathematically this law may be written as V∞T V=KT OR V/T=K This relation shows that the ratio of volume of a given mass of a gas to its absolute temperature is always constant provided the pressure is kept constant. On this bases Charles Law may also be defined as, If the pressure remains constant for each 1ºC change of temperature the volume of the gas changes to 1/273 of its original volume. On the bases of this statement V1 / T = K & V2 / T2 = K V1 / T1 = V2 / T2 This equation is known as Charle's equation. The volume temperature relationship can be represented graphically. When volume of a given mass of gas is plotted against temperature, a straight line is obtained. Graph Coming Soon

Absolute Scale Of Temperature There are different scales for the measurement of temperature such as Celsius ºC and Fahrenheit ºC. Similarly another scale known as absolute scale or Kelvin scale is determined on the basis of Charle's law. On the basis of Charle's law we known that the volume of the gas changes to 1/273 times of its original volume for each 1 ºC change of temperature. It suggests that the volume of a gas would theoretically be zero at -273ºC. But this temperature has never been achieved for any gas because all the gases condense to liquid at a temperature above this point. So the minimum possible temperature for a gaseous system is to be -273ºC. This temperature is referred as absolute zero or zero degree of the absolute scale or Kelvin scale. To form an absolute scale thermometer if the equally spaced divisions of centigrade thermometer are extended below zero and when the point -273ºC is maked then this point is called as absolute

zero and the scale is called as absolute scale. It shows that for the conversion of centigrade scale into Kelvin scale 273 is added to the degrees on the centigrade scale. K = 273 + ºC

Avogadro's Law In 1811, a scientist Avogadro's established a relationship between the volume and number of molecules of the gas, which is known as Avogadro's law. Statement Equal volume of all gases contains equal number of molecules under the same condition of temperature & pressure. Mathematically it may be represented as V∞n OR V=Kn On the basis of the above statement we can say that 1 dm3 of O2 gas will contain the same number of molecules as 1 dm3 of H2 or N2 or any other gas at same temperature and pressure. It was also observed that 22.4 dm3 of any gas at S.T.P contain 1 mole of that gas, so 22.4 dm3 volume at S.T.P is called as molar volume or the volume of 1 mole of the gas and the mass present in 22.4 dm3 of any gas will be equal to its molar mass or molecular mass. It can also be explained on the basis of following figures. Determination of Unknown Molecular Mass of a Gas With the Help of Avogadro's Law Suppose we have two gases (i) Oxygen (ii) CO The volume of these two gases are equal which are 1 dm3. The mass of 1 dm3 of oxygen is 1.43 gm The mass of 1 dm3 of Co is 1.25 gm According to Avogadro's law we know that 1 dm3 of CO at S.T.P contain the same number of molecules as 1 dm3 of O2 under similar condition. Hence a molecule of CO has 1.25 / 1.43 times as much as a molecule of O2 and we know that the molecular mass of oxygen is 32 so the molecular mass of CO would be 1.25 / 1.43 x 32 = 28 g / mole General Gas Equation (Ideal Gas Equation) To give a relation between the volume, pressure and number of moles of n gas, Boyle's law, Charle's law and Avogadro's law are used. According to Boyle's law | V ∞ 1 / P According to Charle's law | V ∞ T According to Avogadro's law | V ∞ n By combining these laws we get V∞1/PxTxn OR V=Rx1/PxTxP OR PV=nRT

This equation is known as general gas equation n is also known as equation of state because when we specify the four variables = pressure, temperature, volume and number of moles we define the state for a gas. In this equation "R" is a constant known as gas constant. Value of R 1. When Pressure is Expressed in Atmosphere and Volume in Litres or dm3 According to general gas equation PV=nRT OR R = PV / nT For 1 mole of a gas at S.T.P we know that V = 22.4 dm3 or litres T = 273 K (standard temperature) P = 1 atm (standard pressure) So, R = PV / nT = 1 atm x 22.4 dm3 / 1 mole x 273 K = 0.0821 dm3 K-1 mol0-1 2. When Pressure is Expressed in Newtons Per Square Metre and Volume in Cubic Metres For 1 mole of a gas at S.T.P V = 0.0224 m3 .......... ( 1 dm3 = 10-3 m3) n = 1 mole T = 273 K P = 101200 Nm-2 So, R = PV / nT = 101300 Nm-2 x 0.0224 m3 / 1 mole x 273 K = 8.3143 Nm K-1 mole-1 = 8.3143 J K-1 mol-1 Derivation of Gas Equation According to general gas equation PV=nRT For 1 mole of a gas n = 1 PV=RT OR PV/T=R Consider for a known mass of a gas the volume of the gas is V1 at a temperature T1 and pressure P1. Therefore for this gas we can write as P1 V1 / T1 = R If this gas is heated to a temperature T2 due to which the pressure is changed to P2 and volume is changed to V2. For this condition we may write as P2 V2 / T2 = R P1 V1 / T1 = P2 V2 / T2 = R

P1 V1 / T1 = P2 V2 / T2 This equation is known as gas equation.

Graham's Law of Diffusion We know that gas molecules are constantly moving in haphazard direction, therefore when two gases are placed separated by a porous membrane, they diffuse through the membrane and intermix with each other. The phenomenon of mixing of molecules of different gases is called diffusion. In 1881, Graham established a relationship between the rates of diffusion of gases and their densities which is known as Graham's law of diffusion. Statement The rate of diffusion of any gas is inversely proportional to the square root of its density. Mathematically it can be represented as r ∞ 1 / √d r = K / √d Graham also studied the comparative rates of diffusion of two gases. On this basis the law os defined as The comparative rates of diffusion of two gases under same condition of temperature and pressure are inversely proportional to the square root of their densities. If the rate of diffusion of gas A is r1 and its density is d1 then according to Graham's law r1 ∞ 1 / √d1 OR r1 = K / √d1 Similarly the rate of diffusion of gas B is r2 and its density is d2 then r2 ∞ 1 / √d2 OR r2 = K / √d2 Comparing the two rates r1 / r2 = (K / √d1) / (K / √d2) r1 / r2 = √d2 / d1 ................... (A) But density d = mass / volume Therefore, For d1 we may write as d1 = m1 / v1 And for d2 d2 = m2 / v2 Substituting these values of d1 & d2 in equation (A) r1 / r2 = √(m2 / v2) / (m1 / v1) But v1 = v2 because both gases are diffusing in the same volume. Therefore, r1 / r2 = √m2 / m1 Hence Graham's law can also be stated as, The comparative rates of diffusion of two gases are inversely proportional to the square root of their masses under the same condition of temperature and pressure.

It means that a lighter gas will diffuse faster than the heavier gas. For example compare the rate of diffusion of hydrogen and oxygen. Rate of diffusion of H2 / Rate of diffusion of O2 = √Mass of O2 / Mass of H2 = √32/ 2 = √16 = 4 It shows that H2 gas which is lighter gas than O2 will diffuse four times faster than O2.

Dalton's Law of Partial Pressures Partial Pressure In a gaseous mixture the individual pressure oxerted by a gas is known as partial pressure. When two or more gases which do not react chemically are mixed in the same container each gas will exert the same pressure as it would exert if it alone occupy the same volume. John Dalton in 1801 formulated a law which is known as Dalton's Law of partial pressure and stated as. Statement The total pressure of a gaseous system is equal to the sum of the partial pressures of all the gases present in the system. Suppose in a system three gases A, B & C are present. The partial pressure of these gases are PA = Partial pressure of gas A PB = Partial pressure of gas B PC = Partial pressure of gas C Then Dalton's law may be mathematically written as PT = PA + PB + PC Where PT is the total pressure of the system. To calculate the individual pressures of gases in the above example suppose the number of moles of A, B & C in the container are nA, nB and nC. So the total number of moles in the container will be n = nA + nB + nC Apply the general gas equation PV=nRT PT = n R T / V Since R, T and V are same for gases A, B and C, therefore the partial pressure of these gases are as follows. Partial pressure of gas A | PA = n(A)RT / V ......... (2) Partial pressure of gas B | PB = n(B)RT / V ......... (3) Partial pressure of gas C | PC = n(C)RT / V ......... (4) Now divide equation (2) by (1) PA / PT = (nA RT/V) / (nRT/V) OR PA / PT = nA / nT Therefore, P(gas) = P1 x n(gas) / n(total) Application of Dalton's Law In an inert mixture of gases the individual gas exerts its own pressure due to collision of its molecules with the walls of the container but the total pressure produced on the container wall

will be the sum of pressure of all the individual gases of the mixture. On this basis the number of moles formed during a chemical reaction can be measured. For this purpose a gas produced in a chemical reaction is collected over water. The gas also contains some of water vapours. So the pressure exerted by the gas would be the pressure of pure gas and the pressure of water vapours. Therefore the pressure of the system may be represented as P(moist) = P(dry) + P(water vapour) So, P(dry) = P(moist) - P(water vapour) In this way we can obtain the pressure of the gas and by using general gas equation we can calculate the number of moles of the prepared gas.

Ideal Gas A gas which obeys all the gas laws at all temperatures and pressures is known as ideal gas. It means that the product of pressure and volume must be constant at all pressures. Similarly the rate of V/T will remain constant for an ideal gas. But there is no gas which is perfectly ideal because of the presence of the force of attraction or repulsion between the molecules.

Gas Laws on the Basis of Kinetic Theory Boyle's Law According to Boyle's law the volume of a given mass of a gas is inversely proportional to its pressure at constant temperature. It means that when the volume of the gas is decreased the pressure of the gas will increase. According to kinetic molecular theory of gases the pressure exerted by a gas is due to the collisions of the molecules with the walls of the container. If the volume of a gas is reduced at constant temperature, the average velocity of the gas molecules remains constant so they collide more frequently wit the walls which causes higher pressure. Charle's Law According to Charles law the volume of a given mass of a gas is directly proportional to its absolute temperature at constant pressure. According to kinetic molecular theory the average kinetic energy of gas molecules is directly proportional to its absolute temperature so if the temperature of the gas is increased the average kinetic energy of the gas molecules is also increased due to which the sample of the gas expanded to keep the pressure constant. It is accordance with the law. Graham's Law According to Graham's Law r1 / r2 = √m2 / m1 The rate of diffusion of a gas is directly proportional to the velocity of the molecules so, v1 / v2 = √m2 / m1

Liquefaction According to kinetic theory, the kinetic energy of the molecules is low for lower temperature. These slower moving molecules become subject to inter molecular attraction. At a sufficiently low temperature these attractive forces are capable of holding the molecules with one another so the gas is changed into liquid and the process is called liquefaction. Liquid State It is one of the state of matter. In this state, the kinetic energy of the molecule is very high due to which the molecules of the liquid are able to move but due to compact nature liquids are not compressible. On this basis we can say that the volume of a liquid is always constant but its shape can be changed. Behaviour of Liquids The main properties of liquids are as follows. Diffusibility The diffusion of one liquid into another liquid is possible but its rate is slow as compared with the rate of diffusion of gases. Example of diffusion of liquids is mixing of alcohol in water. Explanation of Diffusion in of Kinetic Energy As the molecular of a liquid are in cluster form they are very close to each other but these molecules are movable so they can mix with the other molecules. Since the intermolecular distance are smaller due to which the rate of diffusion of liquids is slow. Compressibility The space between liquid molecules are very small due to strong Van der Waals forces. When the pressure is applied, they can be compressed but to a very little extent. Expansion When a liquid is heated, the kinetic energy of its molecules also increases so the attraction between the molecules becomes weaker due to which they go further apart and hence the liquid expands. Contraction When a liquid is cooled its kinetic energy is lowered and the attraction among the molecules becomes stronger so they comes close to each other and hence the liquid contract.

Viscosity Definition The internal resistance in the flow of a liquid is called viscosity. Liquids have the ability to flow, but different liquids have different rates of flow. Some liquids like honey mobil oil etc. flow slowly and are called viscous liquids while ether, gasoline etc. which flow quickly are called less viscous. Explanation

The viscosity of liquid can be understood by considering a liquid in a tube, a liquid in a tube is considered as made up of a series of molecular layer. The layer of the liquid in with the walls of the tube remains stationary and the layer in the center of the tube has highest velocity as shown. Each layer exerts a drag on the next layer and causes resistance to flow.

Factors on Which Viscosity Depends 1. Size of Molecules The viscosity of a liquid depends upon the size of its molecules. If the size of the molecules is bigger the viscosity of the liquid is high. 2. Shape of Molecules Shape of the molecules affects the viscosity. If the shapes of the molecules are spherical they can move easily but if the shapes of the molecules are irregular such as linear or trigonal then the molecules will move slowly and its viscosity will be high. 3. Intermolecular Attraction If the force of attraction between the molecules of a liquid is greater the viscosity of the liquid is also greater. 4. Temperature Viscosity of a liquid decreases with the increase of temperature.

Units of Viscosity Viscosity of a liquid is measured in poise, centipoise or millipoise & S.I unit. 1 poise = 1 N.s.m(-2) 1 centipoise = 10(-2) N.s.m(-2)

Surface Tension Definition The force acting per unit length on the surface of a liquid at right angle direction is called surface tension. Explanation Consider a liquid is present in a beaker. The molecules inside the liquid are surrounded by the other molecules of the liquid. So the force of attraction on a molecule is balanced from all direction. But the force of attraction acting on the molecules of the surface from the lower layer molecules is not balanced. The molecules lying on the surface are attracted by the molecules present below the surface Due to this downward pull the surface of the liquid behave as a membrane which tends to contract to a smaller area and causes a tension on the surface of the liquid known as surface tension. Diagram Coming Soon

Factors on Which Surface Tension Depends 1. Molecular Structure of the Liquid If the force of attraction between the molecules is greater, the surface tension of the liquid is also greater. Those liquids in which hydrogen bond formation take place will have more surface tension. 2. Temperature Surface tension of a liquid is inversely proportional to the temperature. Units 1. Dynes / cm 2. Ergs / cm2 Capillary Action The fall or rise of a liquid in a capillary tube is called capillary action. When a capillary tube is dipped in a liquid which wets the wall of the tube, the liquid will rise in the capillary tube, to decrease the surface area due to surface tension. The liquid will rise in the capillary tube until the upward force due to surface tension is just balanced by the downward gravitational pull. This is called capillary action.

Vapour Pressre Definition The pressure exerted by the vapours of a liquid in its equilibrium state with the pure liquid at a given temperature is called vapour pressure. Explanation Consider a liquid is present in a bottle as shown. Diagram Coming Soon In the beginning the atmosphere above the surface of liquid is unsaturated but due to continuous evaporation the molecule of the liquid are trapped in the bottle and the air present above the surface of the liquid is becomes saturated and after it the molecules present in the vapour state may hit the liquid again and re it by condensing into liquid. Thus in this closed vessel two process are going on simultaneously which are evaporation and condensation of vapours. When the rates of these two processes becomes equal at this point the pressure exerted by vapours is called vapour pressure.

Units of Vapour Pressure The units for vapour pressure are 1. Millimeter of Hg 2. Atmosphere 3. Torr 4. Newton / m(2)

Factors for Vapour Pressure 1. Nature of Liquid Vapour pressure of a liquid depends upon the nature of the liquid. Low boiling liquid exert more vapour pressure at a given temperature. 2. Temperature Vapour pressure of a liquid also depends upon temperature. The vapour pressure of the liquid increases with the increase of temperature due to the increase of average of kinetic energy. 3. Intermolecular Forces Those liquids in which the intermolecular forces are weak shows high vapour pressure. Explanation of Evaporation on the Basis of Kinetic Theory According to this theory the molecules of a liquid collide with each other during their motion. Due to these collisions some of the molecules acquire greater energy than Van der Walls forces which binds the molecules of the liquid together so these molecules of higher energy escapes from the surface into the air in the form of vapours. Evaporation is a Cooling Process In liquids, due to collision between molecules some molecules acquire higher energy and escapes from the surface of the liquid in the form of vapours. The kinetic energy of the remaining molecules decreases due to which the temperature of the liquid also decreases and hence we can say that evaporation is a cooling process.

Boiling Point Definition The temperature at which the vapour pressure of a liquid becomes equal to the atmospheric pressure is called boiling point. When a liquid is heated the rate of evaporation of the molecules also increases with the increase in temperature. When the pressure of the vapours becomes equal to the atmospheric pressure the liquid starts boiling and this temperature is known as boiling point. If the external pressure on a liquid is changed the boiling point of the liquid also change. The increase in external pressure on a liquid increases the boiling point while the decreases of external pressure decrease the boiling point.

Solid State It is a state of matter which posses both definite shape and definite volume. In solids the particles are very close to each and tightly packed with a greater force of attraction.

Properties of Solids

1. Diffusibility Diffusion also occurs in solids but its rate is very slow. If a polished piece of zinc is clamped with a piece of copper for a long time. After few years we will see that some particles of zinc are penetrated into copper and some particles of copper are penetrated into zinc. It shows that the diffusion in solids is possible but it occurs with a slow rate. 2. Compressibility In solids the molecules are close to each other so it is not easy to compress a solid. In other words we can say that the effect of pressure on solids is negligible. 3. Sublimation It is a property of some solids that on heating these solids are directly converted into vapours without liquification. This property of solids is known as sublimation. 4. Melting When solids are heated, they are changed into liquids and the property is called melting of the solids. 5. Deformity Solids may be deformed by high pressure. When a high pressure is applied on solids due to which some particles are dislocated the force of attraction is so strong that the rearranged atoms are held equally well with their new neighbours and hence the solid is deformed.

Classification of Solids Solids are classified into two main classes. 1. Crystalline 2. Amorphous 1. Crystalline Solids In a solid if the atoms are attached with each other with a definite arrangement and it also possesses a definite geometrical shape. This type of solid is called crystalline solid. e.g. NaCl, NiSO4 are crystalline solids. 2. Amorphous Solids In these solids there is no definite arrangement of the particles so they do not have a definite shape. The particles of such solids have a random three dimensional arrangement. Examples of amorphous solids are glass, rubber, plastic etc. The properties of crystalline and amorphous solids are quite different from each other. These differences in properties are given below. Difference of Geometry 1. Crystalline Solids In crystalline solids particles are arranged in a definite order due to which it possesses a definite structure. 2. Amorphous Solids

In amorphous solids particles are present without any definite arrangement so they do not have definite shape. Difference of Melting Point 1. Crystalline Solids Crystalline solids have sharp melting point due to uniform arrangement. 2. Amorphous Solids Amorphous solids melts over a wide range of temperature. Cleavage and Cleavage Plane 1. Crystalline Solids When a big crystal is broken down into smaller pieces the shape of the smaller crystals is identical with the bigger crystal. This property of crystalline solids is called cleavage and the plane from where a big crystal is broken is called cleavage plane. 2. Amorphous Solids Amorphous solids do not break up into smaller pieces with an identical shape. Anisotropy & Isotropy 1. Crystalline Solids It is a property of crystalline solid that they show different physical properties in different direction. For example graphite can conduct electric current only through the plane which is parallel to its layers. This property is called anisotropy. 2. In amorphous solids the physical properties are same in all directions. This property of solids is called isotropy. Symmetry in Structure 1. Crystalline solids are symmetric in their structure when they are rotated about an axis, their appearance remains same so they are symmetric in structure. 2. Amorphous Solids Amorphous solids are not symmetric.

Types of Crystals There are four types of crystals. 1. Atomic crystals 2. Ionic crystals 3. Covalent crystals 4. Molecular crystal 1. Atomic Crystals Metals are composed of atoms. These atoms are combined with each other by metallic bond and the valency electrons in metals can move freely throughout the crystal lattice. This type of solid is called atomic crystal. The properties of atomic crystals are 1. High melting point. 2. Electrical and thermal conductivity.

3. These are converted into sheets so these are malleable. 4. These are used as wire so these are ductile. 2. Ionic Crystals Those solids which consists of negativity and positively charged ions held together by strong electrostatic force of attraction are called ionic crystals. Ionic crystalline solids possesses the following properties. 1. The melting and boiling point of ionic crystals is high. 2. They conduct electricity in molten state. 3. Ionic crystals are very hard. 4. Indefinite growth of crystals is also a property of ionic crystals. 3. Covalent Crystals In covalent solids, the atoms or molecules are attached with each other by sharing of electrons. Such type of solids are called covalent solids e.g. diamond is a covalent solid in which carbon atoms are attached with each other by covalent bond. The other examples of covalent crystals are sulphur, graphite etc. Covalent crystals possesses the following properties. 1. High melting point. 2. High refractive index. 3. Low density. 4. Molecular Crystals Those solid in which molecules are held together due to intermolecular forces to form a crystal lattice are called molecular crystals e.g. iodine and solid CO2 are molecular crystals. The general properties of molecular crystals are as follows. 1. Low melting and boiling point. 2. Non - conductor of heat and electricity.

Isomorphism When two different substance have same crystalline structure, they are said to be isomorphous and the phenomenon is called isomorphism. e.g. ZnSO4 and NiSO4 are two different substances but both are orthorhombic similarly the structure of CaCO3 and NaNO3 is frigonal.

Polymorphism If a substance exist in more than one crystalline form it is called polymorphous and the phenomenon is known as polymorphism. E.g. sulphur exist in rhombic and monoclinic form similarly CaCO3 exist in trigonal and orthorhombic form.

Unit Cell

The basic structural unit of a crystalline solid which when repeated in three dimensions generates the crystal structure is called a unit cell. A unit cell of any crystalline solid has a definite geometric shape and distinguish from other crystals on the basis of length of the edges and angle between the edges.

Crystal Lattice In crystalline solids atoms, ions or molecules are arranged in a definite order and form a three dimensional array of particles which is known as crystal lattice.

Atomic Structure Introduction About the structure of atom a theory was put on by John Dalton in 1808. According to this theory matter was made from small indivisible particles called atoms. But after several experiments many particles have been discovered with in the atom which are electrons, protons, neutrons, positrons etc. For the discovery of these fundamental particles the experiments are as follows. 1. Faraday's experiment indicates the existence of electron. 2. Crook's tube experiment explains the discovery of electron and proton. 3. Radioactivity also confirms the presence of electrons and protons. 4. Chadwick's experiment shows the presence of neutrons. The details of these experiments are given below.

Faraday's Experiment age of Electricity Through Solution In this experiment Faraday ed the electricity through an electrolytic solution. He observed that when two metal plates called electrodes are placed in an electrolytic solution and electricity is ed through his solution the ions present in the solution are moves towards their respective electrodes. In other words these ions are moves towards the oppositely charge electrodes to give up their charge and liberated as a neutral particles. Faraday also determined the charges of different ions and the amount of elements liberated from the electrolytic solution. Due to this experiment presence of charge particles in the structure of atoms is discovered. The basic unit of electric charge was later named as electron by Stoney in 1891. Diagram Coming Soon

Crook's Tube Or Discharge Tube Experiment age of Electricity Through Gases Under Low Pressure Introduction The first of the subatomic particles to be discovered was electron. The knowledge about the

electron was derived as a result of the study of the electric discharge in the discharge tube by J.J. Thomson in 1896. This work was later extended by W. Crooke Working of Discharge Tube When a very high voltage about 10,000 volts is applied between the two electrodes, no electric discharge occurs until the part of the air has been pumped out of the tube. When the pressure of the gas inside the tube is less than 1 mm, a dark space appears near the cathode and thread like lines are observed in the rest of 0.01 mm Hg it fills the whole tube. The electric discharge es between the electrodes and the residual gas in the tube begins to glow. These rays which proceed from the cathode and move away from it at right angle in straight lines are called cathode rays. Properties of Cathode Rays 1. They travel in straight lines away from the cathode and produce shadow of the object placed in their path. 2. The rays carry a negative charge. 3. These rays can also be easily deflected by an electrostatic field. 4. The rays can exert mechanical pressure showing that these consist of material particle which are moving with kinetic energy. 5. The produce fluorescence when they strike the glass wall of the discharge tube. 6. Cathode rays produce x-rays when they strike a metallic plate. 7. These rays consists of material particle whose e/m resembles with electron. 8. These rays emerge normally from the cathode and can be focused by using a concave cathode. Positive Rays In 1890 Goldstein used a discharge tube with a hole in the cathode. He observed that while cathode rays were emitting away from the cathode, there were coloured rays produced simultaneously which ed through the perforated cathode and caused a glow on the wall opposite to the anode. Thomson studied these rays and showed that they consisted of particles carrying a positive charge. He called them positive rays. Properties of Positive Rays 1. These rays travel in a straight line in a direction opposite to the cathode. 2. These are deflected by electric as well as magnetic field in the way indicating that they are positively charged. 3. The charge to mass ratio (e/m) of positive particles varies with the nature of the gas placed in the discharge tube. 4. Positive rays are produced from the ionization of gas and not from anode electrode. 5. Positive rays are deflected in electric field. This deflection shows that these are positively charged so these are named as protons. The Information Obtained From Discharge Tube Experiment The negatively charge particles electrons and the positively charge particles protons are the fundamental particle of every atom.

Radioactivity

In 1895, Henry Becqueral observed that uranium and its compounds spontaneously emitted certain type of radiation which affected a photographic plate in the dark and were able to penetrate solid matter. He called these rays as radioactivity rays and a substance which possessed the property of emitting these radioactivity rays was said to be radioactivity element and the phenomenon was called radioactivity. On further investigation by Maric Curic, it was found that the radiation emitted from the element uranium as well as its salts is independent of temperature and the source of the mineral but depend upon the mineral but depend upon the quantity of uranium present e.g. Pitchblende U3O8 was found to be about four times more radioactive than uranium. Radioactive Rays Soon after the discovery of radium it was suspected that the rays given out by radium and other radioactive substance were not of one kind. Rutherford in 1902 devised an ingenious method for separating these rays from each other by ing them between two oppositely charged plate. It was observed that the radioactive rays were of three kinds, the one bending towards the negative plate obviously carrying positive charge were called α-rays and those deflected to the positive plate and carrying -ve charge were named as β-rays. The third type gamma rays, unaffected and carry no charge. Properties of α - RAYS 1. These rays consists of positively charged particles. 2. These particles are fast moving helium nuclei. 3. The velocity of α-particles is approximately equal to 1/10th of the velocity of light. 4. Being relatively large in size, the penetrating power of α-rays is very low. 5. They ionize air and their ionization power is high. Properties of β - RAYS 1. These rays consists of negatively charged particles. 2. These particles are fast moving electron. 3. The velocity of β-particles is approximately equal to the velocity of light. 4. The penetrating power of β-rays is much greater than α-rays. 5. These rays ionizes gases to lesser extent. Properties of γ - RAYS 1. Gamma rays do not consist of particles. These are electromagnetic radiations. 2. They carry no charge so they are not deflected by electric or magnetic field. 3. Their speed is equal to that of light. 4. These are weak ionizer of gases. 5. Due to high speed and non-material nature they have great power of penetration.

Chadwick Experiment (Discovery of Neutron) When a light element is bombarded by α-particles, these α-particles leaves the nucleus in an unstable disturbed state which on settling down to stable condition sends out radioactivity rays. The phenomenon is known as "Artificial Radioactivity".

In 1933, Chadwick identified a new particle obtained from the bombardment of beryllium by αparticles. It had a unit mass and carried no charge. It was named "Neutron".

Spectroscopic Experiment After the discovery of fundamental particles which are electrons, protons & neutron, the next question concerned with electronic structure of atom. The electronic structure of the atom was explained by the spectroscopic studies. In this connection Plank's Quantum theory has great impact on the development of the theory of structure of atom.

Planck's Quantum Theory In 1900, Max Planck studied the spectral lines obtained from hot body radiations at different temperatures. According to him, When atoms or molecules absorb or emit radiant energy, they do so in separate units of waves called Quanta or Photons. Thus light radiations obtained from excited atoms consists of a stream of photons and not continuous waves. The energy E of a quantum or photon is given by the relation E=hv Where v is the frequency of the emitted radiation and h the Planck's constant. The value of h = 6.62 x 10(-27) erg. sec. The main point of this theory is that the amount of energy gained or lost is quantized which means that energy change occurs in small packets or multiple of those packets, hv, 2 hv, 3 hv and so on.

Spectra A spectrum is an energy of waves or particles spread out according to the increasing or decreasing of some property. E.g. when a beam of light is allowed to through a prism it splits into seven colours. This phenomenon is called dispersion and the band of colours is called spectrum. This spectrum is also known as emission spectrum. Emission spectra are of two types. 1. Continuous Spectrum 2. Line Spectrum 1. Continuous Spectrum When a beam of white light is ed through a prism, different wave lengths are refracted through different angles. When received on a screen these form a continuous series of colours bands: violet, indigo, blue, green, yellow and red (VIBGYOR). The colours of this spectrum are so mixed up that there is no line of demarcation between different colours. This series of bands that form a continuous rainbow of colours is called continuous spectrum. Diagram Coming Soon 2. Line Spectrum

When light emitted from a gas source es through a prism a different kind of spectrum may be obtained. If the emitted from the discharge tube is allowed to through a prism some discrete sharp lines on a completely dark back ground are obtained. Such spectrum is known as line spectrum. In this spectrum each line corresponds to a definite wave length. Diagram Coming Soon Identification of Element By Spectrum Each element produces a characteristics set of lines, so line spectra came to serve as "finger prints" for the identification of element. It is possible because same element always emit the same wave length of radiation. Under normal condition only certain wave lengths are emitted by an element.

Rutherford's Atomic Model Evidence for Nucleus and Arrangement of Particles Having known that atom contain electrons and a positive ion, Rutherford and Marsden performed their historic "Alpha particle scattering experiment" in 1909 to know how and where these fundamental particles were located in the structure of atom. Rutherford took a thin of gold with thickness 0.0004 cm and bombarded in with α-particles. He observed that most of the α-particles ed straight through the gold foil and thus produced a flash on the screen behind it. This indicated that old atoms had a structure with plenty of empty space but some flashes were also seen on portion of the screen. This showed that gold atoms deflected or scattered α-particles through large angles so much so that some of these bounced back to the source. Based on these observations Rutherford proposed a model of the atom which is known as Rutherford's atomic model. Diagram Coming Soon Assumption Drawn From the Model 1. Atom has a tiny dense central core or the nucleus which contains practically the entire mass of the atom leaving the rest of the atom almost empty. 2. The entire positive charge of the atom is located on the nucleus. While electrons were distributed in vacant space around it. 3. The electrons were moving in orbits or closed circular paths around the nucleus like planets around the sun. 4. The greater part of the atomic volume comprises of empty space in which electrons revolve and spin. Weakness of Rutherford Atomic Model According to the classical electromagnetic theory if a charged particle accelerate around an oppositely charge particle it will radiate energy. If an electron radiates energy, its speed will decrease and it will go into spiral motion finally falling into the nucleus. Similarly if an electron moving through orbitals of ever decreasing radii would give rise to radiations of all possible frequencies. In other words it would given rise to a continuous spectrum. In actual practise, atom gives discontinuous spectrum.

X-Rays and Atomic Number In 1895, W.Roentgen discovered that when high energy electrons from cathode collide with the anode in the Crook's tube, very penetrating rays are produced. These rays were named as X-rays. Explanation When an electron coming from the cathode strike with the anode in the crook's tube, it can remove an electron from the inner shell of the atom. Due to removal of t his electron the electronic configuration of this ion is unstable and an electron from an orbital of higher energy drops into the inner orbital by emitting energy in form of a photon. This photon corresponds to electromagnetic radiations in the x-rays region.

Relationship Between Wave Length and Nuclear Charge In 1911, Mosley stablished a relationship between the wave length and nuclear charge. He found that when cathode rays struck elements used as anode targets in the discharge tube, characteristic x-rays were emitted. The wave length of the x-rays emitted decreases regularly with the increase of atomic mass. On careful examination of his data Mosely found that the number of positive charges on the nucleus increases from atom to atom by single electronic unit. He called the number of positive charges as the atomic number. Diagram Coming Soon

Bohr's Theory Rutherford's model of atom fails to explain the stability of atom and appearance of the line spectra. Bohr in 1913 was the first to present a simple model of the atom which explained the appearance of line spectra. Some of the postulates of Bohr's theory are given below. 1. An atom has a number of stable orbits or stationary states in which an electron can reside without emission or absorption of energy. 2. An electron may from one of these non-radiating states to another of lower energy with the emission of radiations whose energy equals the energy difference between the initial and final states. 3. In any of these states the electrons move in a circular path about the nucleus. 4. The motion of the electron in these states is governed by the ordinary laws of mechanics and electrostatic provided its angular momentum is an integral multiple of h/2π It can be written as mvr = nh / 2π Here mvr becomes the angular momentum of the electron. Thus Bohr's first condition defining the stationary states could be stated as "Only those orbits were possible in which the angular momentum of the electrons would be an integral multiple of h/2π". These stationary states correspond to energy levels in the atom. Calculation of Radius of Orbits Consider an electrons of charge e revolving.

Atomic number and e the charge on a proton. Let m be the mass of the electro, r the radius of the orbit and v the tangential velocity of the revolving electron. The electrostatic force of attraction between the nucleus and the electron according to Coulomb's law = Z e x e / r2 Diagram Coming Soon The centrifugal force acting on the electron. = mv2 / r Bohr assumed that these two opposing forces must be balanced each other exactly to keep the electron in an orbit. Therefore Ze2 / r2 = m v2 / r Multiply both sides by r r x Ze2 / r2 = r x m v2 / r Ze2 / r = m v2 OR r = Ze2 / m v2 .................. (1) The Bohr's postulate states that only those orbits are possible in which mvr = nh / 2π Therefore, V = nh / 2πmr Substituting the value of V in eq (1) r = Ze2 / m(nh/2πmr)2 or r = Ze2 x 4π2 mr2/n2h2 or 1/r = 4π2mZe2/n2h2 cr r = n2h2 / 4π2mZe2 ............... (2) This equation gives the radii of all the possible stationary states. The values of constants present in this equation are as follows. H = 6.625 x 10(-27) ergs sec OR 6.625 x 10(-37) J.s Me = 9.11 x 10(-28) gm OR 9.11 x 10(-31) kg E = 4.802 x 10(-10) e.s.u OR 1.601 x 10(-19) C By substituting these values we get for first shell of H atom r = 0.529 x 10(-8) m OR 0.529 The above equation may also be written as r = n2 (h2 / 4π2mZe2) x n2 a0 .................... (3) For the first orbit n = 1 and r = 0.529. This is the value of the in the brackets sometimes written as a0 called Bohr's Radius. For the second shell n = 2 and for 3rd orbit n = 3 and so on.

Hydrogen Atom Spectrum Balmer Series The simplest element is hydrogen which contain only one electron in its valence shell.

Balmer in 1885 studied the spectrum of hydrogen. For this purpose he used hydrogen gas in the discharge tube. Balmer observed that hydrogen atom spectrum consisted of a series of lines called Balmer Series. Balmer determined the wave number of each of the lines in the series and found that the series could be derived by a simple formula. Lyman Series Lyman series is obtained when the electron returns to the ground state i.e. n = 1 from higher energy level n(2) = 2, 3, 4, 5, etc. This series of lines belongs to the ultraviolet region of spectrum. Paschen Series Paschen series is obtained when the electron returns to the 3rd shell i.e. n = 3 from the higher energy levels n2 = 4, 5, 6 etc. This series belongs to infrared region. Bracket Series This series is obtained when an electron jumps from higher energy levels to 4th energy level.

Heisenberg Uncertainty Principle According to Bohr's theory an electron was considered to be a particle but electron also behaves as a wave according to be Broglie. Due to this dual nature of electron in 1925 Heisenberg gave a principle known as Heisenberg Uncertainty Principle which is stated as, It is impossible to calculate the position and momentum of a moving electron simultaneously. It means that if one was known exactly it would be impossible to known the other exactly. Therefore if the uncertainty in the determination of momentum is Δpx and the uncertainty in position is Δx then according to this principle the product of these two uncertainties may written as Δpx . Δx ≈ h So if one of these uncertainties is known exactly then the uncertainty in its determination is zero and the other uncertainty will become infinite which is according to the principle.

Energy Levels and Sub-Levels According to Bohr's atomic theory, electrons are revolving around the nucleus in circular orbits which are present at definite distance from the nucleus. These orbits are associated with definite energy of the electron increasing outwards from the nucleus, so these orbits are referred as Energy Levels or Shells. These shells or energy levels are designated as 1, 2, 3, 4 etc K, L, M, N etc. The spectral lines which correspond to the transition of an electron from one energy level to another consists of several separate close lying lines as doublets, triplets and so on. It indicates that some of the electrons of the given energy level have different energies or the electrons belonging to same energy level may differ in their energy. So the energy levels are accordingly divided into sub energy levels which are denoted by letters s, p, f (sharp, principle, diffuse &

fundamental). The number of sub levels in a given energy level or shell is equal to its value of n. e.g. in third shell where n = 3 three sub levels s, p, d are possible.

Quantum Numbers There are four quantum numbers which describe the electron in an atom. 1. Principle Quantum Number It is represented by "n" which describe the size of orbital or energy level. The energy level K, L, M, N, O etc correspond to n = 1, 2, 3, 4, 5 etc. If n = 1 the electron is in K shell n = 2 the electron is in L shell n = 3 the electron is in M shell 2. Azimuthal Quantum Number This quantum number is represented by "l" which describes the shape of the orbit. The value of Azimuthal Quantum number may be calculated by a relation. l = 0 ----> n - 1 So for different shell the value of l are as n = 1 K Shell l = 0 n = 2 L Shell l = 0, 1 n = 3 M Shell l = 0, 1, 2 n = 4 N Shell l = 0, 1, 2, 3 when l = 0 the orbit is s when l = 1 the orbit is p when l = 2 the orbit is d when l = 3 the orbit is f 3. Magnetic Quantum Number It is represented by "m" and explains the magnetic properties of an electron. The value of m depends upon the value of l. It is given by m = + l ----> 0 ----> l when l = 1, m has three values (+1, 0, -1) which corresponds to p orbital. Similarly when l = 2, m has five values which corresponds to d orbital. 4. Spin Quantum Number It is represented by "s" which represents spin of a moving electron. This spin may be either clockwise or anticlockwise so the values for s may be +1/2 or -1/2.

Pauli's Exclusion Principle

According to this principle No two electrons in the same atom can have the same four quantum number. Consider an electron is present in 1s orbital. For this electron n = 1, l = 0, m = 0. Suppose the spin of this electron is s = +1/2 which will be indicated by an upward arrow ↑. Now if another electron is put in the same orbital (1s) for that electron n = 1, l = 0, m = 0. It can occupy this orbital only if the direction of its spin is opposite to that of the first electron so s = -1/2 which is symbolized by downward arrow ↓. From this example, we can observe the application of Pauli's exclusion principle on the electronic structure of atom.

Electronic Configuration The distribution of electrons in the available orbitals is proceeded according to these rules. 1. Pauli Exclusion Principle 2. Aufbau Principle 3. (n + l) Rule 4. Hund's Rule The detail of these rules and principles is given below. 1. Aufbau Principle It is states as The orbitals are filled up with electrons in the increasing order of their energy. It means that the orbitals are fulled with the electrons according to their energy level. The orbitals of minimum energy are filled up first and after it the orbitals of higher energy are filled. 2. Hund's Rule If orbitals of equal energy are provided to electron then electron will go to different orbitals and having their parallel spin. In other words we can say that electrons are distributed among the orbitals of a sub shell in such a way as to give the maximum number of unpaired electrons and have the same direction of spin. 3. (n + l) Rule According to this rule The orbital with the lowest value of (n + l) fills first but when the two orbitals have the same value of (n + l) the orbital with the lower value of n fills first. For the electronic configuration the order of the orbital is as follows. 1s, 2s, 2p, 3s, 4s, 3d, 4p, 5s, 4d, 5p, 6s etc.

Atomic Radius For homonuclear diatomic molecules the atomic radius may be defined as The half of the distance between the two nuclei present in a homonuclear diatomic molecules is called atomic radius. It may be shown as In case of hetronuclear molecular like AB, the bond length is calculated which is (rA + rB) and if radii of any one is known the other can be calculated.

For the elements present in periodic table the atomic radius decreases from left to right due to the more attraction on the valence shell but it increases down the group with the increase of number of shells.

Ionic Radius Ionic radius is defined as The distance between nucleus of an ion and the point up to which nucleus has influence of its electron cloud. When an electron is removed from a neutral atom the atom is left with an excess of positive charge called a cation e.g Na ----> Na+ + cBut when an electron is added in a neutral atom a negative ion or anion is formed. Cl + e- ----> ClAs the atomic radius, the ionic radii are known from x-ray analysis. The value of ionic radius depends upon the ions that surround it. Ionic radii of cations have smaller radii than the neutral atom because when an electron is removed. The effective charge on the nucleus increases and pulls the remaining electrons with a greater force. Ionic radii of anions have a large radii than the neutral atom because an excess of negative charge results in greater electron repulsion. Radius of Na atom = 1.57 Radius of Na+ atom = 0.95 (smaller than neutral atom) Radius of Cl atom = 0.99 Radius of Cl- atom = 1.81 (larger than neutral atom)

Ionization Potential Definition The amount of energy required to remove most loosely bounded electron from the outermost shell of an atom in its gaseous state is called is called ionization potential energy. It is represented as M(gas) ----> M+(gas) + e- ................... ΔE = I.P The energy required to remove first electron is called first I.P. The energy required to remove 2nd or 3rd electron is called 2nd I.P or 3rd I.P M(gas) ----> M+(gas) + e- ................... ΔE = 1st I.P M+(gas) ----> M++(gas) + e- ................ΔE = 2nd I.P M++(gas) ----> M+++(gas) + e- ............ ΔE = 3rd I.P The units of I.P is kilo-Joule per mole. Factors on which I.P Depends 1. Size of the Atom If the size of an atom is bigger the I.P of the atom is low, but if the size of the atom is small then the I.P will be high, due to fact if we move down the group in the periodic table. The I.P value decreases down the group.

2. Magnitude of Nuclear Charge If the nuclear charge of atom is greater than the force of attraction on the valence electron is also greater so the I.P value for the atom is high therefore as we move from left to right in the periodic table the I.P is increased. 3. Screening Effect The shell present between the nucleus and valence electrons also decreases the force of attraction due to which I.P will be low for such elements.

Electron Affinity Definition The amount of energy liberated by an atom when an electron is added in it is called electron affinity. It shows that this process is an exothermic change which is represented as Cl + e- ----> Cl- ............ ΔH = -348 kJ / mole Factors on which Electron Affinity Depends 1. Size of the Atom If the size of atom is small, the force of attraction from the nucleus on the valence electron will be high and hence the E.A for the element will also be high but if the size of the atoms is larger the E.A for these atoms will be low. 2. Magnitude of the Nuclear Charge Due to greater nuclear charge the force of attraction on the added electron is greater so the E.A of the atom is also high. 3. Electronic Configuration The atoms with the stable configuration has no tendency to gain an electron so the E.A of such elements is zero. The stable configuration may exist in the following cases. 1. Inert gas configuration 2. Fully filled orbital 3. Half filled orbital

Electronegativity Definition The force of attraction by which an atom attract a shared pair of electrons is called electronegativity. Application of Electronegativity 1. Nature of Chemical Bond If the difference of electronegativity between the two combining atoms is more than 1.7 eV, the nature of the bond between these atoms is ionic but if the difference of electronegativity is less

than 1.7 eV then the bond will be covalent. 2. Metallic Character If an element possesses high electronegativity value then this element is a non-metal but if an element exist with less electronegativity, it will be a metal. Factors for Electronegativity 1. Size of the Atom If the size of the atom is greater the electronegativity of the atom is low due to the large distance between the nucleus and valence electron. 2. Number of Valence Electrons If the electrons present in the valence shell are greater in number, the electronegativity of the element is high.

Chemical Bond Introduction Atoms of all the elements except noble gases have incomplete outermost orbits and tends to complete them by chemical combination with the other atoms. In 1916, W Kossel described the ionic bond which is formed by the transfer of electron from one atom to another and also in 1916 G.N Lewis described about the formation of covalent bond which is formed by the mutual sharing of electrons between two atoms. Both these scientists based their ideas on the fact that atoms greatest stability when they acquire an inert gas electronic configuration. Definition When two or more than two atoms are combined with each other in order to complete their octet a link between them is produced which is known as chemical bond. OR The force of attraction which holds atoms together in the molecule of a compound is called chemical bond. Types of Chemical Bond There are three main types of chemical bond. 1. Ionic bond or electrovalent bond 2. Covalent bond 3. Co-ordinate covalent bond or Dative covalent bond

Ionic Bond OR Electrovalent Bond Definition A chemical bond which is formed by the complete shifting of electron between two atoms is called ionic bond or electrovalent bond. OR

The electrostatic attraction between positive and negative ions is called ionic bond. Conditions for the Ionic Bond Formation 1. Electronegativity Ionic bond is formed between the element having a difference of electronegativity more than 1.7 or equal to 1.7 eV. Therefore ionic bond is generally formed between metals (low electronegative) and non-metal (high electronegative) elements. 2. Ionization Potential We know that ionic bond is formed by the transference of electron from one atom to another, so in the formation of ionic bond an element is required which can lose its electrons from the outer most shell. It is possible to remove electron from the outermost shell of metals because of their low ionization potential values. 3. Electron Affinity In the formation of ionic bond an element is also required which can gain an element is also required which can gain electron, since non-metals can attract electrons with a greater force due to high electronegativity. So a non-metal is also involved in the formation of ionic bond due to high electron affinity. Example of Ionic Bond In order to understand ionic bond consider the example of NaCl. During the formation of Ionic bond between Na and Cl2, Sodium loses one electron to form Na+ ion while chlorine atom gains this electron to form Cl- ion. When Na+ ion and Cl- ion attract to each other NaCl is formed. The stability of NaCl is due to the decrease in the energy. These energy change which are involved in the formation of ionic bond between Na and Cl are as follows. i. Sodium has one valence electron. In order to complete its octet Na loses its valence electron. The loss of the valence electron required 495 kJ/mole. Na ----> Na+ + e- ....................... ΔH = 495 kJ/mole ii. Chlorine atom has seven electrons in its valence shell. It require only one electron to complete its octet, so chlorine gains this electron of sodium and release 348 kJ/mole energy. Cl + e- ----> Cl- ...................... ΔH = -348 kJ/mole Here the energy difference is 147 kJ/mole (495 - 348 = 147). This loss of energy is balanced when oppositely charged ions are associated to form a crystal lattice. iii. In third step, positively charged Na+ ion and negatively charged Cl- ion attract to each other and a crystal lattice is formed with a definite pattern. Na+(g) + Cl-(g) ----> Na+Cl- ........... ΔH = - 788 kJ/mole This energy which is released when one mole of gaseous ions arrange themselves in definite pattern to form lattice is called lattice energy. From this example, we can conclude that it is essential for the formation of ionic bond that the sum of energies released in the second and third steps must be greater than the energy required for the first step. Characteristics of Ionic Compounds

1. An ionic compounds, the oppositely charged ions are tightly packed with each other, so these compounds exist in solid state. 2. Due to strong attractive forces between ions a larger amount of energy is required to melt or to boil the compound and hence the melting and boiling point of the ionic compound are generally high. 3. Ionic compounds are soluble in water but insoluble in organic solvents like benzene, CCl4. etc. 4. In the aqueous solution, the ionic compounds are good electrolytes, because in water the interionic forces are so weakened that the ions are separated and free to move under the influence of electric current. Due to this free movement of ions, the ionic compounds conduct electricity in their solutions.

Covalent Bond Definition A link which is formed by the mutual sharing of electrons between two atoms is called covalent bond. Explanation In the formation of covalent bond, mutual sharing of electron takes place. This mutual sharing is possible in non-metals, therefore covalent bond is generally formed between the atoms of nonmetals. For example In Cl2 molecule, two atoms of chlorine are combined with each other to form Cl2 molecule. Each atom of chlorine having seven electrons in its valencies shell. These atoms are united with each other by sharing one of its valence electron as shown. Cl Cl: ----> :Cl :Cl OR Cl - Cl In this molecule, one shared pair of electrons forms a single covalent bond between two chlorine the atoms. With the formation of a covalent bond the energy of the system is also decreased. Cl + Cl ----> Cl - Cl .............. ΔH = - 242 kJ / mole This released energy lowered the energy of the molecule and the stability of the compound is also increased. Types of Covalent Bond There are three main types of covalent bond. 1. Single Covalent Bond When a covalent bond is formed by sharing of one electron from each atom, that it is called single covalent bond and denoted by (-) single line between the two bonded atoms e.g. Cl - Cl, H - H, H - Br etc. 2. Double Covalent Bond In a covalent bond, if two electrons are shared from each of the bonded atom then this covalent bond is called double covalent bond and denoted by (=) two lines e.g. O = O, O : : O 3. Triple Covalent Bond

When a covalent bond is formed by sharing of three electrons from each atom then this type of covalent bond is called triple covalent bond, and denoted by (≡) three lines between the two bonded atoms e.g. N : : N :, N ≡ N The bond distance of multiple bonds are shorter and the bond energies are higher. Characteristics of Covalent Compounds The main characteristics properties of covalent compounds are as follows 1. The covalent compounds exist as separate covalent molecules, because the particles are electrically neutral so they es solid, liquid or gaseous state. This intermolecular force of attraction among the molecules. 2. Since the covalent compound exist in all the three states of matter so their melting points and boiling point may be high or low. 3. Covalent compounds are non-electrolytes so they do not conduct electricity from their aqueous solution. 4. Covalent compounds are generally insoluble in water and similar polar solvent but soluble in the organic solvents.

Co-Ordinate OR Dative Covalent Bond Definition It is a type of covalent bond in which both the shared electrons are donated only be one atom, this type is called co-ordinate covalent bond. The ∞ ordinate covalent bond between two atoms is denoted by an arrow (→). The atom which donates an electron pair is called as a donor of electron and the other atom involved in this bond is called acceptor. E.g. A + B ----> A : B OR A → B

Dipole Moment Definition The product of the charge and the distance present in a polar molecules is called dipole moment and represented by μ. OR The extent of tendency of a molecule to be oriented under the influence of an electric field is called dipole moment. Mathematical Representation of Dipole Moment Suppose the charge present on a polar molecule is denoted by e and the separation between the two oppositely charged poles of the molecules is d, then the product of these two may be written as exd=μ Where μ is dipole moment. Dipole Moment in Diatomic Molecules

The diatomic molecules which are made up of similar atoms will be non-polar and their dipole moment is zero but the diatomic molecules made up of two different atoms e.g. HCl or Hl are polar and have some dipole moment. The value of the dipole moment depends upon the difference of electronegativities of the two bonded atom. If the difference of electronegativity between the atoms is greater, the polarity and also the dipole moment of the molecule is greater e.g. The dipole moment of HCl = 1.03 debye Whereas dipole moment of HF = 1.90 debye Dipole Moment of Poly Atomic Molecules In poly atomic molecules, the dipole moment of molecules depends upon the polarity of the bond as well as the geometry of the molecule.

Ionic Character of Covalent Bond In homonuclear diatomic molecules like Cl2, O2, l2, H2 both the atoms are identical so the shared electrons are equally attracted due to identical electronegativities and hence the molecules are non-polar. When two dissimilar atoms are linked by a covalent bond the shared electrons are not attracted equally by the two bonded atoms. Due to unsymmetrical distribution of electrons one end of the molecules acquire partial positive charge and the other end acquire a partial negative charge. This character of a covalent bond is called Ionic character of a covalent bond. The ionic character of a covalent bond depends upon the difference of electronegativity of the two dissimilar atoms ed with each other in a covalent bond. E.g., the H-F bond is 43% ionic whereas the H-Cl bond is 17% ionic. The ionic character greatly affects the properties of a molecules e.g., melting point, boiling point of polar molecules are high and they are soluble in polar solvent like H2O. Similarly the presence of partial polar character shortens the covalent bond and increases the bond energies.

Bond Energy Definition The amount of energy required to break a bond between two atoms in a diatomic molecule is known as Bond Energy. OR The energy released in forming a bond from the free atoms is also known as Bond Energy. It is expressed in kilo Joules per mole or kCal/mole. Examples i. The bond energy for hydrogen molecule is H - H(g) ----> 2 H(g) .......................... ΔH = 435 kJ/mole OR H(g) + H(g) ----> H - H ....................... ΔH = 435 kJ/mole It can be observed from this example that the breaking of bond is endothermic whereas the formation of the bond is exothermic.

ii. The bond energy for oxygen molecule is O = O(g) ----> 2 O(g) ........................ ΔH = 498 kJ/mole OR O(g) + O(g) ----> O = O .................... ΔH = -498 kJ/mole Bond energy of a molecule also measure the strength of the bond. Generally bond energies of polar bond are greater than pure covalent bond. E.g. Cl - Cl ----> 2 Cl ........................ ΔH = 244 kJ/mole H - Cl ----> H+ + Cl- ................... ΔH = 431 kJ/mole The value of bond energy e.g., triple bonds are usually shorter than the double bond therefore the bond energy for triple bond is greater than double bond.

Sigma & PI Bond Sigma Bond Definition When the two orbitals which are involved in a covalent bond are symmetric about an axis, then the bond formed between these orbitals is called Sigma Bond. OR A bond which is formed by head to head overlap of atomic orbitals is called Sigma Bond. Explanation In the formation of a sigma bond the atomic orbital lies on the same axis and the overlapping of these orbital is maximum therefore, all such bonds, in which regions of highest density around the bond axis are termed as sigma bond. Types of Overlapping in Sigma Bond There are three types of overlapping in the formation of sigma bond. 1. s-s orbitals overlapping 2. s-p orbitals overlapping 3. p-p orbitals overlapping In all the three types, when the two atomic orbitals are overlapped with each other two molecular orbitals are formed. In these two molecular orbitals the energy of one orbital is greater than the the atomic orbitals which is known as sigma antibonding orbital while the energy of the other orbital is less than the atomic orbital this orbital of lower energy is called sigma bonding orbital and the shared electron are always present in the sigma bonding orbitals. 1. s-s Orbitals Overlapping In order to explain s-s overlapping consider the example of H2 molecule. In this molecule is orbital of one hydrogen overlaps with is orbital of other hydrogen to form sigma bonding orbitals. Due to this bonding a single covalent bond is formed between the two hydrogen atoms. Diagram Coming Soon 2. s-p Orbitals Overlapping This type of overlapping takes place in H-Cl molecule. 1s orbital of hydrogen overlaps with 1p

orbital of chlorine to form a single covalent bond. In this overlapping two molecular orbitals are formed, one of the lower energy while the other orbital is of higher energy. The shapes of these orbitals are as follows. Diagram Coming Soon 3. p-p Orbitals Overlapping This type of overlapping takes place in fluorine molecule. In this mole 1p orbital of a fluorine atom is overlapped with 1p orbital of the other fluorine atom. The molecular orbitals formed in this overlapping are given in figure Diagram Coming Soon PI Bond When the two atomic orbital involved in a covalent bond are parallel to each other then the bond formed between them is called pi bond. In this overlapping, two molecular orbitals are also formed. The lower energy molecular orbitals is called π bonding orbital while the higher energy molecular orbital is called π antibonding orbital. The shape of these molecular orbitals are as follows. Diagram Coming Soon

Hybridization Definition The process in which atomic orbitals of different energy and shape are mixed together to form new set of equivalent orbitals of the same energy and same shape. There are many different types of orbital hybridization but we will discuss here only three main types. 1. sp3 Hybridization The mixing of one s and three p orbitals to form four equivalent sp3 hybrid orbitals is called sp3 hybridization. These sp3 orbitals are directed from the center of a regular tetrahedron to its four corners. The angles between tetrahedrally arranged orbitals are 109.5º. It has two partially filled 2p orbitals which indicate that it is divalent, but carbon behaves as tetravalent in most of its compounds. It is only possible if one electron from 2s orbital is promoted to an empty 2pz orbital to get four equivalent sp3 hybridized orbitals. Diagram Coming Soon The four sp3 hybrid orbitals of the carbon atom overlap with 1s orbitals of four hydrogen atoms to form a methane CH4 molecule. The methane molecule contains four sigma bonds and each H-C-H bond angle is 109.5º. 2. sp2 Hybridization The mixing of one s and two p orbitals to form three orbitals of equal energy is called sp2 or 3sp2 hybridization. Each sp2 orbital consists of s and p in the ratio of 1:2. These three orbitals are co-planar and at 120º angle as shown Diagram Coming Soon A typical example of this type of hybridization is of ethane molecule. In ethylene, two sp2 hybrid orbitals of each carbon atom share and overlap with 1s orbitals of two hydrogen atoms to form

two σ bonds. While the remaining sp2 orbital on each carbon atom overlaps to form a σ bond. The remaining two unhybridized p orbitals (one of each) are parallel and perpendicular to the axis ing the two carbon nuclei. These generates a parallel overlap and results in the formation of 2 π orbitals. Thus a molecule of ethylene contain five σ bonds and one π bond. Diagram Coming Soon 3. sp Hybridization When one s and one p orbitals combine to give two hybrid orbitals the process is called sp hybridization. The sp hybrid orbitals has two lobes, one with greater extension in shape than the other and the lobes are at an angle of 180º from each other. It means that the axis of the two orbitals form a single straight line as shown. Now consider the formation of acetylene molecule HC ≡ CH. The two C-H σ bonds are formed due to sp-s overlap and a triple bond between two carbon atoms consist of a σ bond and two π bond. The sigma bond is due to sp-sp overlap whereas π bonds are formed as a result of parallel overlap between the unhybridized four 2p orbitals of the two carbon. Diagram Coming Soon

Valence Shell Electron Pair Repulsion Theory The covalent bonds are directed in space to give definite shapes to the molecules. The electrons pairs forming the bonds are distributed in space around the central atom along definite directions. The shared electron pairs as well as the lone pair of electrons are responsible for the shape of molecules. Sidwick and Powell in 1940 pointed out that the shapes of the molecules could be explained on the basis of electron pairs present in the outermost shell of the central atom. Pairs of electrons around the central atom are arranged in space in such a way so that the distances between them are maximum and coulombie repulsion of electronic cloud are minimized. The known geometries of many molecules based upon measurement of bond angles shows that lone pairs of electrons occupy more space than bonding pairs. The repulsion between electronic pairs in valence shell, decreases in the following order. Lone Pair - Lone Pair > Lone Pair - Bond Pair > Bond Pair - Bond Pair When we apply this theory we can see the variation of angle in the molecular structures. Consider the molecular structures of NH3, OH & H2O. Diagram Coming Soon Variation from ideal bond angles are caused by multiple covalent bonds and lone electron pairs both of which require more space than single covalent bonds and therefore cause compression of surrounding bond angles. Thus the number of pairs of electrons in the valency shell determine the overall molecular shape. Structure of BeCl2 The two bond pairs of electrons in BeCl2 arrange themselves as far apart as possible in order to minimize the repulsion between them. Structure of BF3 OR BCl3 In this molecule three bond pair are present around boron to arrange themselves as far apart as possible a trigonal structure is formed.

Hydrogen Bond When hydrogen is bonded with a highly electronegative element such as nitrogen oxygen, fluorine, the molecule will be polarized and a dipole is produced. The slightly positive hydrogen atom is attracted by the slightly negatively charged electronegative atom. An electrostatic attraction between the neighbouring molecules is set up when the positive pole of one molecule attracts the negative pole of the neighbouring molecule. This type of attractive force which involves hydrogen is known as hydrogen bonding.

Energetics Of Chemical Reaction Thermodynamics Definition It is branch of chemistry which deals with the heat energy change during a chemical reaction. Types of Thermochemical Reactions Thermo-chemical reactions are of two types. 1. Exothermic Reactions 2. Endothermic Reactions 1. Exothermic Reaction A chemical reaction in which heat energy is evolved with the formation of product is known as Exothermic Reaction. An exothermic process is generally represented as Reactants ----> Products + Heat 2. Endothermic Reaction A chemical reaction in which heat energy is absorbed during the formation of product is known as endothermic reaction. Endothermic reaction is generally represented as Reactants + Heat ----> Products Thermodynamic 1. System Any real or imaginary portion of the universe which is under consideration is called system. 2. Surroundings All the remaining portion of the universe which is present around a system is called surroundings. 3. State The state of a system is described by the properties such as temperature, pressure and volume when a system undergoes a change of state, it means that the final description of the system is different from the initial description of temperature, pressure or volume.

Properties of System The properties of a system may be divided into two main types. 1. Intensive Properties Those properties which are independent of the quantity of matter are called intensive properties. e.g. melting point, boiling point, density, viscosity, surface, tension, refractive index etc. 2. Extensive Properties Those properties which depends upon the quantity of matter are called extensive properties. e.g. mass, volume, enthalpy, entropy etc.

First Law of Thermodynamics This law was given by Helmheltz in 1847. According to this law Energy can neither be created nor destroyed but it can be changed from one form to another. In other words the total energy of a system and surroundings must remain constant. Mathematical Derivation of First Law of Thermodynamics Consider a gas is present in a cylinder which contain a frictionless piston as shown. Diagram Coming Soon Let a quantity of heat q is provided to the system from the surrounding. Suppose the internal energy of the system is E1 and after absorption of q amount of heat it changes to E2. Due to the increase of this internal energy the collisions offered by the molecules also increases or in other words the internal pressure of the system is increased after the addition of q amount of heat. With the increase of internal pressure the piston of the cylinder moves in the upward direction to maintain the pressure constant so a work is also done by the system. Therefore if we apply first law of thermodynamics on this system we can write q = E2 - E1 + W OR q = ΔE + W OR ΔE = q - W This is the mathematical representation of first law of thermodynamics. Pressure - Volume Work Consider a cylinder of a gas which contain a frictionless and weightless piston, as shown above. Let the area of cross-section of the piston = a Pressure on the piston = P The initial volume of the gases = V1 And the final volume of the gases = V2 The distance through which piston moves = 1 So the change in volume = ΔV = V2 - V1 OR ΔV = a x 1 The word done by the system W = force x distance W = Pressure x area x distance

W=Pxax1 W=PΔV By substituting the value of work the first law of thermodynamics may be written as q = ΔE + P ΔV The absorption or evolution of heat during chemical reaction may take place in two ways. 1. Process at Constant Volume Let qv be the amount of heat absorbed at constant volume. According to first law qv = ΔE + P ΔV But for constant volume ΔV = O Therefore, P ΔV = P x O = O So, qv = ΔE + 0 Or qv = ΔE Thus in the process carried at constant volume the heat absorbed or evolved is equal to the energy ΔE. 2. Process at Constant Pressure Let qp is the amount of heat energy provided to a system at constant pressure. Due to this addition of heat the internal energy of the gas is increased from E1 to E2 and volume is changed from V1 to V2, so according to first law. qp = E2 - E1 + P(V2 - V1) Or qp = E2 - E1 + PV2 - PV1 Or qp = E2 + PV2- E1 - PV1 Or qp = (E2 + PV2) - (E1 - PV1) But we known that H = E + PV So E1 + PV1 = H1 And E2 + PV2 = H2 Therefore the above equation may be written as qp = H2 - H1 Or qp = Δ H This relation indicates that the amount of heat absorbed at constant pressure is used in the enthalpy change. Sign of ΔH ΔH represent the change of enthalpy. It is a characteristic property of a system which depends

upon the initial and final state of the system. For all exothermic processes ΔH is negative and for all endothermic reactions ΔH is positive.

Thermochemistry It is a branch of chemistry which deals with the measurement of heat evolved or absorbed during a chemical reaction. The unit of heat energy which are generally used are Calorie and kilo Calorie or Joules and kilo Joules. 1 Cal = 4.184 J OR 1 Joule = 0.239 Cal

Hess's Law of Constant Heat Summation Statement If a chemical reaction is completed in a single step or in several steps the total enthalpy change for the reaction is always constant. OR The amount of heat absorbed or evolved during a chemical reaction must be independent of the particular manner in which the reaction takes place. Explanation Suppose in a chemical reactant A changes to the product D in a single step with the enthalpy change ΔH Diagram Coming Soon This reaction may proceed through different intermediate stages i.e., A first changes to B with enthalpy change ΔH1 then B changes to C with enthalpy change ΔH2 and finally C changes to D with enthalpy ΔH3. According to Hess's law ΔH = ΔH1 + ΔH2 + ΔH3 Verification of Hess's Law When CO2 reacts with excess of NaOH sodium carbonate is formed with the enthalpy change of 90 kJ/mole. This reaction may take place in two steps via sodium bicarbonate. In the first step for the formation of NaHCO3 the enthalpy change is -49 kJ/mole and in the second step the enthalpy change is -41 kJ/mole. According to Hess's Law ΔH = ΔH1 + ΔH2 ΔH = -41 -49 = -90 kJ/mole The total enthalpy change when the reaction is completed in a single step is -90 kJ/mole which is equal to the enthalpy change when the reaction is completed into two steps. Thus the Hess's law is verified from this example.

Chemical Equilibrium Reversible Reactions Those chemical reactions which take place in both the directions and never proceed to completion are called Reversible reaction. For these type of reaction both the forward and reverse reaction occur at the same time so these reaction are generally represented as Reactant □ Product The double arrow □ indicates that the reaction is reversible and that both the forward and reverse reaction can occur simultaneously. Some examples of reversible reactions are given below 1. 2Hl □ H2 + l2 2. N2 + 2 H2 □ 2 NH3

Irreversible Reactions Those reactions in which reactants are completely converted into product are called Irreversible reaction. These reaction proceed only in one direction. Examples of such type of reaction are given below 1. NaCl + AgNO3 ----> AgCl + NaNO3 2. Cu + H2SO4 ----> CuSO4 + H2

Equilibrium State The state at which the rate of forward reaction becomes equal to the rate of reverse reaction is called Equilibrium state. Explanation Consider the following reaction A+B□C+D It is a reversible reaction. In this reaction both the changes (i.e. forward & backward) occur simultaneously. At initial stage reactant A & B are separated from each other therefore the concentration of C and D is zero. When the reaction is started and the molecules of A and B react with each other the concentration of reactant is decreased while the concentration of product is increased. With the formation of product, the rate of forward reaction decreased with time but the rate of reverse reaction is increased with the formation of product C & D. Ultimately a stage reaches when the number of reacting molecules in the forward reaction equalizes the number of reacting molecules in the reverse direction, so this state at which the rate of forward reaction becomes equal to the rate of reverse reaction is called equilibrium state.

Law of Mass Action

Statement The rate at which a substance reacts is proportional to its active mass and the rate of a chemical reaction is proportional to the product of the active masses of the reactant. The term "active mass" means the concentration in of moles/dm3. Derivation of Equilibrium Constant Expression Consider in a reversible reaction "m" mole of A and "n" moles of B reacts to give "x" moles of C and "y" moles of D as shown in equation. mA + nB □ xC + yD In this process The rate of forward reaction ∞ [A]m [B]n Or The rate of forward reactin = Kf [A]m [B]n & The rate of reverse reaction ∞ [C]x [D]y Or The rate of reverse reaction = Kf [C]x [D]y But at equilibrium state Rate of forward reaction = Rate of reverse reaction Therefore, Kf [A]m [B]n = Kf [C]x [D]y Or Kf / Kr = [C]x [D]y / [A]m [B]n Or Ke = [C]x [D]y / [A]m [B]n This is the expression for equilibrium constant which is denoted by Ke and defined as The ratio of multiplication of active masses of the products to the product of active masses of reactant is called equilibrium constant. Equilibrium Constant for a Gaseous System Consider in a reversible process, the reactants and product are gases as shown A(g) + B(g) □ C(g) + D(g) When the reactants and products are in gaseous state, their partial pressures are used instead of their concentration, so according to law of mass action. Determination of Equilibrium Constant The value of equilibrium constant K(C) does not depend upon the initial concentration of reactants. In order to find out the value of K(C) we have to find out the equilibrium concentration of reactant and product. 1. Ethyl Acetate Equilibrium Acetic acid reacts with ethyl alcohol to form ethyl acetate and water as shown CH3COOH + C2H5OH □ CH3COOC2H5 + H2O Suppose 'a' moles of acetic acid and 'b' moles of alcohol are mixed in this reaction. After some time when the state of equilibrium is established suppose 'x' moles of H2O and 'x' moles of ethyl acetate are formed while the number of moles of acetic acid and alcohol are a-x and b-x respectively at equilibrium.

According to law of mass action K(C) = [CH3COOC2H5] [H2O] / [CH3COOH] [C2H5OH] K(C) = [x/V] [x/V] / [a-x/V] [b-x/V] K(C) = (x) (x) / (a-x) (b-x) K(C) = x2 / (a-x) (b-x) 2. Hydrogen Iodide Equilibrium For the reaction between hydrogen and iodine suppose a mole of hydrogen and 'b' moles of iodine are mixed in a scaled bulb at 444ºC in the boiling sulphur for some time. The equilibrium mixture is then cooled and the bulbs are opened in the solution of NaOH. Let the amount of hydrogen consumed at equilibrium be 'x' moles which means that the amount of hydrogen left at equilibrium is a-x moles. Since 1 mole of hydrogen reacts with 1 mole of iodine 'o' form two moles of hydrogen iodide hence the amount of iodine used is also x moles so its moles at equilibrium are b-x and the moles of hydrogen iodide at equilibrium are 2x. According to law of mass action K(C) = [Hl]2 / [H2] [l2] K(C) = [2x/V]2 / [a-x/V] [b-x/V] K(C) = 4x2 / (a-x) (b-x) Applications of Law of Mass Action There are two important applications of equilibrium constant. 1. It is used to predict the direction of reaction. 2. K(C) is also used to predict the extent of reaction. To Predict the Direction of Reaction The value of equilibrium constant K(C) is used to predict the direction of reaction. For a reversible process. Reactant □ Product With respect to the ratio of initial concentration of the reagent. There are three possibilities for the value of K 1. It is greater than K(C) 2. It is less than K(C) 3. It is equal to K(C) Case I If [Reactant]initial / [Product]initial > K(C) the reaction will shift towards the reverse direction. Case II If [Reactant]initial / [Product]initial > K(C) the reaction will shift towards the forward direction. Case III If [Reactant]initial / [Product]initial > K(C) this is equilibrium state for the reaction. To Predict the Extent of Reaction

From the value of K(C) we can predict the extent of the reaction. If the value of K(C) is very large e.g. For 2 O3 □ 3 O2 ........... K(C) = 10(55) From this large value of K(C) it is predicted that the forward reaction is almost complete. When the value of K(C) is very low e.g., 2 HF □ H2 + F2 ........... K(C) = 10(-13) From this value it is predicted that the forward reaction proceeds with negligible speed. But if the value of K(C) is moderate, the reaction occurs in both the direction and equilibrium will be attained after certain period of time e.g., K(C) for N2 + 3 H2 □ 2 NH3 ............. is 10 So the reaction occurs in both the direction.

Le Chatelier's Principle Statement When a stress is applied to a system at equilibrium the equilibrium position changes so as to minimize the effect of applied stress. The equilibrium state of a chemical reaction is altered by changing concentration pressure or temperature. The effect of these changes is explained by Le Chatelier. Effect of Concentration By changing the concentration of any substance present in the equilibrium mixture, the balance of chemical equilibrium is disturbed. For the reaction, A+B□C+D K(C) = [C][D] / [A][B] If the concentration of a reactant A or B is increased the equilibrium state shifts tc right and yield of products increases. But if the concentration of C or D is increased then the reaction proceed in the backward direction with a greater rate and more A & B are formed. Effect of Temperature The effect of temperature is different for different type of reaction. For an exothermic reaction the value of K(C) decreased with the increase of temperature so the concentration of products decreases. For a endothermic reaction heat is absorbed for the conversion of reactant into product so if temperature during the reaction is increased then the reaction will proceed with a greater rate in forward direction. ENDOTHERMIC REACTION Temperature increase ----> More products are formed Temperature decrease ----> More reactants are formed EXOTHERMIC REACTION Temperature increase ----> More reactants are formed Temperature decrease ----> More products are formed

Effect of Pressure The state of equilibrium of gaseous reaction is distributed by the change of pressure. There are three types of reactions which show the effect of pressure change. 1. When the Number of Moles of Product are Greater In a reaction such as PCl5 <----> PCl3 + Cl2 The increase of pressure shifts the equilibrium towards reactant side. 2. When the Number of Moles of Reactant are Greater In a reaction such as N2 + 3H2 <----> 2NH3 The increase of pressure shifts the equilibrium towards product side because the no. of moles of product are less than the no. of moles of reactant. 3. When Number of Moles of Reactants and Products are Equal In these reactions where the number of moles of reactant are equal to the number of moles of product the change of pressure does not change the equilibrium state e.g., H2 + l2 □ 2 Hl Since the number of moles of reactants and products are equal in this reaction so the increase of pressure does not affect the yield of Hl. Important Industrial Application of Le Chatelier's Principle Haber's Process This process is used for the production of NH3 by the reaction of nitrogen and hydrogen. In this process 1 volume of nitrogen is mixed with three volumes of hydrogen at 500ºC and 200 to 1000 atm pressure in presence of a catalyst N2 + 3 H2 □ 2 NH3 ............... ΔH = -46.2 kJ/mole 1. Effect of Concentration The value of K(C) for this reaction is K(C) = [NH3]2 / [N2] [H2]3 Increase in concentration of reactants which are nitrogen and hydrogen the equilibrium of the process shifts towards the right so as to keep the value of K(C) constant. Hence the formation of NH3 increases with the increase of the concentration of N2 or hydrogen. 2. Effect of Temperature It is an exothermic process, so heat is liberated with the formation of product. Therefore, according to Le Chatelier's principle at low temperature the equilibrium shifts towards right to balance the equilibrium state so low temperature favours the formation of NH3 3. Effect of Pressure The formation of NH3 proceeds with the decrease in volume, therefore, the reaction is carried out under high pressure or in other words high pressure is favourable for the production of NH3.

Process

The process is used to manufacture H2SO4 on large scale. In this process the most important step is the oxidation of SO2 to SO3 in presence of a catalyst vanadium pentoxide. 2 SO2 + O2 □ 2 SO3 ................... ΔH = - 395 kJ/mole 1. Effect of Concentration The value of K(C) for this reaction is K(C) = [SO3]2 / [SO2]2 [O2] Increase in concentration of SO2 or O2 shifts the equilibrium towards the right and more SO3 is formed. 2. Effect of Temperature Since the process is exothermic, so low temperature will favour the formation of SO3. The optimum temperature for this reaction is 400 to 450ºC. 3. Effect of Pressure In this reaction decrease in volume takes place so high pressure is favourable for the formation of SO3.

Common Ion Effect Statement The process in which precipitation of an electrolyte is caused by lowering the degree of ionization of a weak electrolyte when a common ion is added is known as common ion effect. Explanation In the solution of an electrolyte in water, there exist an equilibrium between the ions and the undissociated molecules to which the law of mass action can be applied. Considering the dissociation of an electrolyte AB we have AB □ A+ + BAnd [A+][B-] / [AB] = K (dissociation constant) If now another electrolyte yielding A+ or B- ions be added to the above solution, it will result in the increase of concentration of the ions A+ or B- and in order that K may remain the same, the concentration AB must evidently increase. In other words the degree of dissociation of an electrolyte is suppressed by the addition of another electrolyte containing a common ion. This phenomenon is known as common ion effect. Application of Common Ion Effect in Salt Analysis An electrolyte is precipitated from its solution only when the concentration of its ions exceed from the solubility product. The precipitates are obtained when the concentration of any one ion is increased. Thus by adding the common ion, the solubility product can be exceeded. In this solution Ou(OH)2 is a weak base while H2SO3 is a strong acid so the pH of the solution is changed towards acidic medium. When Na2CO3 is dissolved in water, it reacts with water such as Na2CO3 + 2 H2O □ 2 NaOH + H2CO3

In this solution H2CO3 which is weak acid an NaOH which is a strong base are formed. Due to presence of strong base the medium is changed towards basic nature.

Solubility Product When a slightly soluble ionic solid such as silver chloride is dissolved in water, it decompose into its ions AgCl □ Ag+ + ClThese Ag+ and Cl- ions from solid phase into solution till the solution becomes saturated. Now there exists an equilibrium between the ions present in the saturated solution and the ions present in the solid phase, thus AgCl □ Ag+ + ClApplying the law of mass action K(C) = [Ag+][Cl-] / [AgCl] Since the concentration of solid AgCl in the solid phase is fixed, no matter how much solid is present in with solution, so we can write. K(C) = [Ag+][Cl-] / K Or K(C) x K = [Ag+][Cl-] Or K(S.P) = [Ag+][Cl-] Where K(S.P) is known as solubility product and defined as The product of the concentration of ions in the saturated solution of a sparingly soluble salt is called solubility product. the value of solubility product is constant for a given temperature. Calculation of Solubility Product From Solubility The mass of a solute present in a saturated solution with a fixed volume of solvent is called solubility, which is generally represented in the unit of gm/dm3. With the help of solubility we can calculate the solubility product of a substance e.g., the solubility of Mg(OH)2 at 25ºC is 0.00764 gm/dm3. To calculate the K(S.P) of Mg(OH)2, first of all we will calculate the concentration of Mg(OH)2 present in the solution. Mass of Mg(OH)2 = 0.00764 gm/dm3 Moles of Mg(OH)2 = 0.00764 / 58 moles / dm3 = 1.31 x 10(-4) moles/dm3 The ionization of Mg(OH)2 in the solution is as follows. Mg(OH)2 □ Mg(+2) + 2 OHAnd the solubility product for Mg(OH)2 may be written as, K(S.P) = [Mg(+2)] [OH-]2 Since in one mole of Mg(OH2) solution one mole of Mg++ ions are present while two moles of OH- ions are present, therefore in 1.31 x 10(-4) mole/dm3 solution of Mg(OH)2, the concentration of Mg(+2) is 1.31 x 10(-4) moles/dm3 while the concentration of OH- is 2. 62 x 10(-8) moles/dm3. By substituting these values K(S.P) = [Mg(+2)][OH-]2 = [1.31 x 10(-4)] [2.62 x 10(-4)]2 = 9.0 x 10(-12) mole3 / dm9

So in this way the solubility product of a substance may be calculated with the help of solubility. Calculation of Solubility from Solubility Product If we know the value of solubility product, we can calculate the solubility of the salt. For example, the solubility of PbCrO4at 25ºC is 2.8 x 10(-13) moles/dm3. m = n2 / w1 in kg m = (w2 / m2) / (w1 / 1000) m = w2 / m2) x (1000 / w1)

Hydration Addition of water or association of water molecules with a substance without dissociation is called Hydration. Water is a good solvent and its polar nature plays very important part in dissolving substances. It dissolves ionic compounds readily. When an ionic compound is dissolved in water, the partial negatively charged oxygen of water molecule is attracted towards the cation ion similarly the partial positively charged hydrogen of water molecule is attracted towards the anions so hydrated ions are formed. Diagram Coming Soon In solution, the number of water molecules which surround the ions is indefinite, but when an aqueous solution of a salt is evaporated the salt crystallizes with a definite number of water molecules which is called as water of crystallization E.g., when CuSO4 recrystallized from its solution the crystallized salt has the composition CuSO4. 5H2O. Similarly when magnesium chloride is recrystallized from the solution, it has the composition MgCl2.6H2O. This composition indicates that each magnesium ion in the crystal is surrounded by six molecules. This type of salts is called hydrated salts. It is observed experimentally that the oxygen atom of water molecule is attached with the cation of salt through co-ordinate covalent bond so it is more better to write the molecular formulas of the hydrated salts as given below. [Cu(H2O)5]SO4 ................. [Mg(H2O)6]Cl2 It is also observed that these compound exist with a definite geometrical structure e.g., the structure of [Mg(H2O)6]Cl2 is octahedral and [Cu(H2O)4]+2 is a square planar. Diagram Coming Soon Factors for Hydration The ability of hydration of an ion depend upon its charge density. For example the charge density of Na+ is greater than K+ because of its smaller size, so the ability of hydration for Na+ is greater than K+ ion. Similarly small positive ions with multiple charges such as Cu(+2), Al(+3), Cr(+3) posses great attraction for water molecules.

Hydrolysis Addition of water with a substance with dissociation into ions is called Hydrolysis. OR The reaction of cation or anion with water so as to change its pH is known as Hydrolysis. Theoritically it is expected that the solution of salts like CuSO4 or Na2CO3 are neutral because these solutions contain neither H+ ion nor OH-, but it is experimentally observed that the solution of CuSO4 is acidic while the solution of Na2CO3 is basic. This acidic or basic nature of solution indicate but H+ ions or OH- ions are present in their solutions which can be produced only by the dissociation of water molecules.

Theory of Ionization

1n 1880, a Swedish chemist Svante August Arrhenius put forward a theory known as theory of ionization, in order to for the conductivity of electrolytes, electrolysis and certain properties of electrolytic solutions. According to this theory. 1. Acids, Bases and Salts when dissolved in water yield two kinds of ions, one carry positive charge and the other carry negative charge. The positively charged ions are called cations which are derived from metals or it may be H+ ion but the negatively charged ions which are known as anions are derived from non-metals NaCl ----> Na+ + ClH2SO4 ----> 2 H+ + SO4(-2) KOH ----> K+ + OH2. Ions in the solution also recombine with each other to form neutral molecules and this process continues till an equilibrium state between an ionized and unionized solid is attained.

Chemical Kinetics Introduction The branch of physical chemistry which deals with the speed or rate at which a reaction occurs is called chemical kinetics. The study of chemical kinetics, therefore includes the rate of a chemical reaction and also the rate of chemical reaction and also the factors which influence its rate.

Slow and Fast Reaction Those reactions for which short time is required to convert a reactant into product are called fast reaction but if more time is required for the formation of a product then the reactions are called slow reactions. Usually ionic reactions which involve oppositely charged ions in aqueous medium are very fast. For example, reaction between aqueous solution of NaCl and AgNO3 gives white precipitates of AgCl instantaneously. AgNO3 + NaCl ----> AgCl + NaNO3 Such reactions are very fast and these are completed in fractions of seconds. But those reactions which involve covalent molecules take place very slowly. For example, conversion of SO2 into SO3 2 SO2 + O2 ----> 2 SO3 It is a slow reaction and required more time for the formation of a product.

Rate Or Velocity of a Reaction Definition It is the change in concentration of a reactant or product per unit time. Mathematically it is represented as Rate of reaction = Change in concentration of reactant or product / Time taken for the change The determination of the rate of a reaction is not so simple because the rate of a given reaction is never uniform. It falls off gradually with time as the reactants are used up. Hence we can not get the velocity or rate of reaction simply by dividing the amount of substance transformed by the time taken for such transformation. For this reason we take a very small interval of time "dt" during which it is assumed that velocity of reaction remains constant. If "dx" is the amount of substance transformed during that small interval of time "dt" then the velocity of reaction is expressed as Velocity of a reaction = dx / dt Thus with the velocity of a chemical reaction we mean the velocity at the given moment or given instant.

The Rate Constant Definition The proportionality constant present in the rate equation is called rate constant.

According to law of mass action we know that the rate of chemical reaction is directly proportional to the molar concentration of the reactants. For example R ----> P The rate of reaction ∞ [R] Or dx / dt = K [R] Where K is known as rate constant. Specific Rate Constant When the concentration and temperature both are specified, the rate constant is known as specific rate constant. When the concentration of each reactant is 1 mole per dm3 at given temperature, the specific rate constant numerically equals to the velocity of the reaction. dx / dt = V = K [R] Or K = V / [R] When R = 1 mole/dm3 K=V But when different reactant are reacting with different number of moles then the value of K may be calculated as 2 SO2 + O2 ----> 2 SO3 = dx / dt = K [SO2]2 [O2] Or K = V / [SO2]2 [O2] Determination of Rate of Reaction There are two method for the determination of rate of a chemical reaction. 1. Physical Method When the rate of a chemical reaction is determined by using physical properties such as colour change, volume change, state change the method known as physical method. 2. Chemical Method In the method the change in concentration of reactant or product is noted and with the help of this change rate of reaction is determined e.g., For the reaction R ----> P Velocity of reaction = - d[R] / dt = + d[P] / dt The negative sign indicates a decrease in concentration of the reactant while positive sign indicates an increase in the concentration of product. Ionization is thus a reversible process. To this process, the law of mass action can be applied as K(C) = [Na+] [Cl-] / [NaCl] 3. The number of positive and negative charges on the ions must be equal so that the solution as a whole remains neutral. 4. The degree of ionization of an electrolyte depends upon (a) the nature of electrolyte, (b) dilution of the solution (c) the temperature

5. When an electric current es through the solution of an electrolyte the positive ions i.e., the cations move towards the cathode and the anions move towards the anode. This movement of ions is responsible for the conductance of electric current through the solution. 6. The electrical conductivity of the solution of an electrolyte depends upon the number of ions present in the solution. On reaching the electrodes, the ions lose their charge and change into neutral atoms or molecules by the gain or loss of electrons. Applications of Arrhenius Theory This theory explain many peculiarities in the behaviour of electrolytic solutions. For example, the elevation in boiling point of 1 molal solution of glucose is 0.52ºC while this elevation in 1 molal solution of NaCl is 1.04ºC. This difference in elevation of boiling point can be explained on the basis of Arrhenius theory. In one molal solution of glucose the number of (molecules) particles are 6.02 x 10(23) per dm3 of solution while in 1 molal solution of NaCl 6.02 x 10(23) ions of Na+ and 6.02 x 10(23) ions of Cl- are present because NaCl is an ionic compound. Since the number of particle are double in NaCl solution, therefore the elevation in boiling point is also double than the solution of glucose. Similarly the other collegative properties such as lowering in vapour pressure, depression in freezing point and osmosis are explained on the basis of this theory. Note Collegative properties are those properties which depends upon the number of particles.

Conductance of Electric Current Through Solutions The ability of a solution to conduct electric current depends upon the ions present in the solution. The conductance of a solution is increased when 1. The solution is diluted 2. The degree of dissociation of the electrolyte is high 3. The temperature of the solution is high 4. The velocity of the ions is high But in a concentrated solution, the number of ions per unit volume of solution increases and the distance between ions decreases causing strong interionic attraction. As a result, migration of ions becomes more difficult and the conductance decreases with increase in concentration. As the conductance is related with the movement of ions, so conductance increase with the increase of absolute velocity of ions in the solution. The conductance of an electrolyte also depends upon the degree of ionization. The degree of ionization is denoted by α and calculated as α = No. of dissociated molecules / Total molecules dissovled

Electrolysis Electrolyte A chemical substance which can conduct electric current in molten form or in its aqueous solution with a chemical change is called electrolyte.

Electrolysis The movement of anions and cations towards their respective electrodes with all accompanying chemical changes in an electrolytic solution under the influence of electric current is known as electrolysis. Explanation To explain the phenomenon of electrolysis consider the example of CuCl2 solution. the ionization of CuCl2 in the solution may be represented as CuCl2 <----> Cu+2 + 2 ClWhen electric current is ed through this solution, the movement of these ions begins to take place Cu+2 ions migrate towards cathode and Cl- ions towards anode. At cathode Cu+2 ions are discharged as copper atoms by the gain of electrons (reduction) Cu+2 + 2 e- ----> Cu(M) ........ Reduction at Cathode At anode Cl- ions are discharged as Cl2 by the loss of electrons (oxidation) 2 Cl- - 2 e- ----> Cl2(g0 ...... Oxidation at Anode The overall reaction of the electrolysis may be written as Cu+2 + 2 e- ----> Cu(M) 2 Cl- - 2 e- ----> Cl2(g) Cu+2 + 2 Cl- ----> Cu(M) + Cl2(g) OR CuCl2 ----> Cu(M) + Cl2(g) When all the ions present in the solution have been changed to neutral particles, the flow of current is stopped.