Bond Angle 45435f

new trick for Bond Angle Chemistry , Physical Chemistry , academic Hello guys ...this is my second article ...(Academic) .... Actually I am submitting this...because there is one question always in JEE, AI EEE...or any State Engineering Exam...on this topic....so make yourself comforta ble ....and understand this... This method is applicable only for element N O P (mean Nitrogen Oxygen and Pho sphorus ) ........... Trick is :If central Atom is same ....then Higher the Electronegativity of Surrounding ato m...lower the bond Angle ...and vice-versa If Surrounding Atom is same...then Lower the Electronegativity of Central atom L ower the bond angle and vice-versa Example ; NF3 NCl3 NBr3 NI3 Central atom is same in all the four case....i.e N...so higher the E.N of Surron ding atom..lower the bond angle... So

EN : F > Cl > Br > I

Hence Bond Angle trend is

NF3 < NCl3 < NBr3 < NI3

PH3 PF3 PCl3 PBr3 PI3

Central Atom is same.....again trend of EN of surrounding atom... F > Cl > Br > I > H ... So bond angle will be PH3 > PI3 > PBr3 > PCl3 > PF3

NH3 PH3

Here surrounding atom is same....but central is different ... So EN of N and P ... N > P So Bond angle of NH3 > PH3 .....( because higher the EN of central atom hig her the Bond Angle )

H2O H2F

Again EN of F > O so H2F > H2O ( Bond angle ) ...this question is asked i n Jee ( I don't the yr)

Solve for this using the above methods .... PF3 NF3 OF2 OCl2 OBr2 OH2 NCl3 PCl3 .....................and see some question from book..if they include some of th is elements ...P N O ....and trend of Bond Angle is asked....then apply this..yo u will get right answer...

I will come up with more tricks...but first waiting for your comments...Did u ge t this method or not...Is it easier than what you mug up....daily ....?