Filter Networks - Network Theory Questions an...

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Filter Networks - Network Theory Questions and Answers by Manish 4-5 minutes

This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “Filter Networks”. 1. The value of one decibel is equal to? a) 0.115 N b) 0.125 N c) 0.135 N d) 0.145 N View Answer Answer: a Explanation: The value of one decibel is equal to 0.115 N. One decibel = 0.115 N where N is the number of nepers and N = loge(V1/V2). 2. A filter which es without attenuation all frequencies up to the cut-off frequency fc and attenuates all other frequencies greater than fc is called? a) high filter b) low filter c) band elimination filter

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d) band filter View Answer Answer: b Explanation: A filter is called a low filter if it es all frequencies up to the cut-off frequency fc without attenuation and attenuates all other frequencies greater than fc. This transmits currents of all frequencies from zero up to the cut-off frequency. 3. A filter which attenuates all frequencies below a designated cut-off frequency fc and es all other frequencies greater than fc is called? a) band elimination filter b) band filter c) low filter d) high filter View Answer Answer: d Explanation: A filter is called high filter if attenuates all frequencies below a designated cut-off frequency fc and es all other frequencies greater than fc. Thus the band of this filter is the frequency range above fc and the stop band is the frequency range below fc. 4. A filter that es frequencies between two designated cut-off frequencies and attenuates all other frequencies is called? a) high filter b) band elimination filter c) band filter 2 of 5

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d) low filter View Answer Answer: c Explanation: A band filter es frequencies between two designated cut-off frequencies and attenuates all other frequencies. A band filter has two cut-off frequencies and will have the band f2-f1; f1 is the lower cut-off frequency, f2 is the upper cut-off frequency. 5. A filter that es all frequencies lying outside a certain range, while it attenuates all frequencies between the two designated frequencies is called? a) low filter b) high filter c) band elimination filter d) band filter View Answer Answer: c Explanation: A band elimination filter es all frequencies lying outside a certain range, while it attenuates all frequencies between the two designated frequencies. It is also referred to as band stop filter. 6. The expression of the characteristic impedance of a symmetrical T-section is? a) ZOT=√(Z12/4-Z1Z2) b) ZOT=√(Z12/4+Z1) c) ZOT=√(Z12/4+Z2)

d) ZOT=√(Z12/4+Z1Z2) View Answer 3 of 5

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Answer: d Explanation: For a T-section, the value of input impedance when it is terminated in Zo is Zin=(Z1/2)+(Z2((Z1/2)+Zo))/((Z1/2)+Z2+Zo) and Zin=Zo. On solving, the expression of the characteristic impedance of a symmetrical T-section is ZOT=√(Z12/4+Z1Z2). 7. The expression of the open circuit impedance Zoc is? a) Zoc=Z1/2+Z2 b) Zoc=Z2/2+Z2 c) Zoc=Z1/2+Z1 d) Zoc=Z1/2-Z2 View Answer Answer: a Explanation: On open circuiting the port 2 of T-section, we get the expression of the open circuit impedance Zoc as Zoc=Z1/2+Z2. 8. The expression of short circuit impedance Zsc is? a) Zsc=(Z12-4Z1Z2)/(2Z1-4Z2)

b) Zsc=(Z12+4Z1Z2)/(2Z1+4Z2) c) Zsc=(Z12-4Z1Z2)/(2Z1+4Z2)

d) Zsc=(Z12+4Z1Z2)/(2Z1-4Z2) View Answer Answer: b Explanation: On short circuiting the port 2 of T-section, we get the expression of short circuit impedance Zsc as Zsc=(Z1/2)+((Z1/2)xZ2)/((Z1/2)+Z2). On solving we get Zsc=(Z12+4Z1Z2)/(2Z1+4Z2).

9. The relation between ZOT, Zoc, Zsc is? 4 of 5

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a) ZOT=√ZocZsc b) Zoc=√(ZOT Zsc) c) Zsc=√(ZOT Zoc) d) Zoc=√(ZOT Zoc) View Answer Answer: a Explanation: Zoc=Z1/2+Z2 and Zsc=(Z12+4Z1Z2)/(2Z1+4Z2) => ZocxZsc=Z1Z2+Z12/4 =Zo2T. The relation between ZOT, Zoc, Zsc is ZOT=√ZocZsc. 10. The value of sinhϒ/2 in of Z1 and Z2 is? a) sinhϒ/2=√(4Z1/Z2) b) sinhϒ/2=√(Z1/Z2) c) sinhϒ/2=√(Z1/4Z2) d) sinhϒ/2=√(2Z1/Z2) View Answer Answer: c Explanation: sinhϒ/2=√((1/2(coshϒ-1)/(1/2(1+Z1/2Z2-1))). The value of sinhϒ/2 in of Z1 and Z2 is sinhϒ/2=√(Z1 /4Z2). Sanfoundry Global Education & Learning Series – Network Theory. To practice all areas of Network Theory, here is complete set of 1000+ Multiple Choice Questions and Answers.

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Network Theory Questions for Entrance Exams


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Network Theory Questions for Entrance Exams by Manish 4-5 minutes

This set of Network Theory Questions and Answers for Entrance exams focuses on “Classification of Band and Stop Band”. 1. The relation between α, β, ϒ is? a) α = ϒ + jβ b) ϒ = α + jβ c) β = ϒ + jα d) α = β + jϒ View Answer Answer: b Explanation: We know that the propogation constant is a complex function and the real part of the complex propogation constant is a measure of the change in magnitude of the current or voltage in the network known as attenuation constant and imaginary part is a measure of the difference in phase between the input and output currents or voltages known as phase shift constant. ϒ = α + jβ. 2. If Z1, Z2 are same type of reactance, then |Z1/4 Z2| is

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real, then the value of α is? a) α = sinh-1√( Z1/4 Z2) b) α = sinh-1√( Z1/Z2)

c) α = sinh-1√( 4 Z1/Z2)

d) α = sinh-1√( Z1/2 Z2) View Answer Answer: a Explanation: Z1, Z2 are same type of reactance and |Z1/4

Z2| is real. |Z1/4 Z2| > 0. The value of α is α = sinh-1√(Z1/4 Z2). 3. If Z1, Z2 are same type of reactance, then |Z1/4 Z2| is real, then? a) |Z1/4 Z2|=0 b) |Z1/4 Z2| < 0 c) |Z1/4 Z2| > 0 d) | Z1/4 Z2|>= 0 View Answer Answer: c Explanation: If Z1 and Z2 are same type of reactances, then √(Z1/4 Z2) should be always positive implies that |Z1/4 Z2|>0. 4. Which of the following expression is true if Z1, Z2 are same type of reactance? a) sinhα/2 sinβ/2=0 b) coshα/2 sinβ/2=0 c) coshα/2 cosβ/2=0 d) sinhα/2 cosβ/2=0 View Answer 2 of 5

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Answer: d Explanation: If Z1, Z2 are same type of reactance, then the real part of sinhϒ/2 = sinhα/2 cosβ/2 + jcoshα/2 sinβ/2 should be zero. So sinhα/2 cosβ/2=0. 5. Which of the following expression is true if Z1, Z2 are same type of reactance? a) sinhα/2 cosβ/2=x b) coshα/2 cosβ/2=0 c) coshα/2 sinβ/2=x d) sinhα/2 sinβ/2=0 View Answer Answer: c Explanation: If Z1, Z2 are same type of reactance, then the imaginary part of sinhϒ/2 = sinhα/2 cosβ/2 + jcoshα/2 sinβ/2 should be some value. So coshα/2 sinβ/2=x. 6. The value of α if Z1, Z2 are same type of reactance? a) 0 b) π/2 c) π d) 2π View Answer Answer: a Explanation: As sinhα/2 cosβ/2=0 and coshα/2 sinβ/2=x, the value of α if Z1, Z2 are same type of reactance is α= 0. 7. The value of β if Z1, Z2 are same type of reactance? a) 2π b) π c) π/2 3 of 5

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d) 0 View Answer Answer: b Explanation: The value of β if Z1, Z2 are same type of reactances, then sinhα/2 cosβ/2=0 and coshα/2 sinβ/2=x. So the value of β is β= π. 8. If Z1, Z2 are same type of reactance, and if α = 0, then the value of β is? a) β=2 sin-1(√(Z1/4 Z2)) b) β=2 sin-1(√(4 Z1/Z2)) c) β=2 sin-1(√(4 Z1/Z2)) d) β=2 sin-1(√(Z1/Z2)) View Answer Answer: a Explanation: If α = 0, sin β/2 = x(√(Z1/4 Z2). But sine can have a maximum value of 1. Therefore the above solution is valid only for Z1/4 Z2, and having a maximum value of unity. It indicates the condition of band with zero attenuation and follows the condition as -1 < Z1/4 Z2 <= 0. So β=2 sin-1(√(Z1/4 Z2)).

9. If the value of β is π, and Z1, Z2 are same type of reactance, then the value of β is? a) α=2 cosh-1√(Z1/2 Z2) b) α=2 cosh-1√(Z1/Z2)

c) α=2 cosh-1√(4 Z1/Z2)

d) α=2 cosh-1√(Z1/4 Z2) View Answer 4 of 5

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Answer: d Explanation: If the value of β is π, cos β/2 = 0. So sin β/2 = ±1; cosh α/2 = x = √(Z1/4 Z2). This solution is valid for negative Z1/4 Z2 and having magnitude greater than or

equal to unity. -α <= Z1/2 Z2 <= -1. α=2 cosh-1√(Z1/4 Z2). 10. The relation between Zoπ, Z1, Z2, ZoT is? a) ZoT = Z1Z2/Zoπ b) Zoπ = Z1Z2/ZoT c) ZoT = Z1Z1/Zoπ d) ZoT = Z2Z2/Zoπ View Answer Answer: b Explanation: The characteristic impedance of a symmetrical π-section can be expressed in of T. Zoπ = Z1Z2/ZoT. Sanfoundry Global Education & Learning Series – Network Theory. To practice all areas of Network Theory for Entrance exams, here is complete set of 1000+ Multiple Choice Questions and Answers.

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Constant-K Low Filter - Network Theory Q...


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Constant-K Low Filter Network Theory Questions and Answers by Manish 3-4 minutes

This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “Constant-K Low Filter”. 1. A network either T or π, is said to be of the constant-k type if Z1 and Z2 of the network satisfy the relation? a) Z1Z2 = k

b) Z1Z2 = k2 c) Z1Z2 = k3

d) Z1Z2 = k4 View Answer Answer: b Explanation: Z1,Z2 are inverse if their product is a constant, independent of frequency, k is real constant, that is the resistance. k is often termed as design impedance or nominal impedance of the constant k-filter. 2. In the circuit shown below, find the value of Z1.

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a) jωL b) 2 jωL c) jωL/2 d) 4 jωL View Answer Answer: a Explanation: The constant k, T or π type filter is also known as the prototype because other more complex networks can be derived from it. From the given figure, the value of Z1 is jωL. 3. In the circuit shown in the question 2, find the value of Z2. a) jωC b) 2 jωC c) 1/jωC d) 1/2 jωC View Answer Answer: c Explanation: From the prototype T section and prototype π section shown in figures, we get the value of Z2 is 1/jωC. 4. The value of Z1Z2 in the circuit shown in the question 2 is? a) L/C b) C/L c) 1/LC 2 of 5

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d) LC View Answer Answer: a Explanation: Z1 = jωL and Z2 = 1/jωC. So the product Z1Z2 is jωL x 1/jωC = L/C. 5. Determine the value of k in the circuit shown in the question 2. a) √LC b) √((L/C) ) c) √((C/L) ) d) √((1/CL) ) View Answer Answer: b Explanation: We got Z1Z2 = L/C. And we know Z1Z2= k2. So k2 = L/C. So the value of k is √(L/C).

6. The cut-off frequency of the constant k-low filter is? a) 1/√LC b) 1/(π√LC) c) √LC d) π√LC View Answer Answer: b Explanation: Z1/4Z2 = 0. Z1 = jωL and Z2 = 1/jωC. On solving the cut-off frequency of the constant k-low filter is fc= 1/(π√LC). 7. The value of α in the band of constant k-low filter is?

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a) 2 cosh-1(fc/f) b) cosh-1(fc/f) c) cosh-1(f/fc)

d) 2 cosh-1(f/fc) View Answer Answer: d Explanation: The value of α in the band of constant k-low filter is α= 2 cosh-1(f/fc). 8. The value of β in the attenuation band of constant k-low filter is? a) 0 b) π c) π/2 d) π/4 View Answer Answer: b Explanation: We know that in the attenuation band, Z1/4Z2 < -1 i.e., f/fc < 1. So the value of β in the band of constant k-low filter is β= π. 9. The value of α in the attenuation band of constant k-low filter is? a) α=2 cosh-1(fc/f) b) α=cosh-1(f/fc)

c) α=2 cosh-1(f/fc) d) α=cosh-1(fc/f) View Answer Answer: c Explanation: α = 2 cosh-1[Z1/4Z2] and Z1/4Z2 = f/fc. On 4 of 5

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substituting we get α = 2 cosh-1(f/fc). 10. The value of α in the band of constant k-low filter is? a) π b) π/4 c) π/2 d) 0 View Answer Answer: d Explanation: We know that in the band, the condition is -1 < Z1/4Z2 < 0. So α= π. Sanfoundry Global Education & Learning Series – Network Theory. To practice all areas of Network Theory, here is complete set of 1000+ Multiple Choice Questions and Answers.

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m-Derived T-Section - Network Theory Question...


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m-Derived T-Section - Network Theory Questions and Answers by Manish 4 minutes

This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “m-Derived T-Section”. 1.The relation between ZoT and ZoT‘ in the circuits shown below.

a) ZoT = ZoT‘

b) ZoT = 2 ZoT‘ c) ZoT = 3 ZoT‘

d) ZoT = 4 ZoT‘

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View Answer Answer: a Explanation: The relation between ZoT and ZoT’ is ZoT = ZoT’ where ZoT’ is the characteristic impedance of the modified (m-derived) T-network. 2. The value of Z2’ in of Z1, Z2 from the circuits shown in question 1 is? a) Z2‘=Z2/4 m (1-m2 )+Z2/m b) Z2‘=Z1/4 m (1-m2 )+Z1/m c) Z2‘=Z2/4 m (1-m2 )+Z1/m

d) Z2‘=Z1/4 m (1-m2 )+Z2/m View Answer Answer: d Explanation: As ZoT = ZoT’, √(Z12/4+Z1Z2)=√(m2 Z12/4+m Z2‘). On solving, Z2‘=Z1/(4 m (1-m2))+Z2/m.

3. The relation between Zoπ and Zoπ’ in the circuits shown below is?

a) Zoπ = 2 Zoπ’

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b) Zoπ = 4 Zoπ’ c) Zoπ = Zoπ’ d) Zoπ = 3 Zoπ’ View Answer Answer: c Explanation: The characteristic impedances of the prototype and its modified sections have to be equal for matching. The relation between Zoπ and Zoπ‘ is Zoπ = Zoπ’. 4. The value of Z1‘ in of Z1, Z2 from the circuits shown in question 3 is? a) Z1‘=(m Z2(Z2 4 m)/(1-m2 ))/m Z1(Z2 4 m/(1-m2 )) b) Z1‘=(m Z1(Z2 4 m)/(1-m2 ))/m Z2(Z2 4 m/(1-m2 )) c) Z1‘=(m Z1(Z2 4 m)/(1-m2 ))/m Z1(Z2 4 m/(1-m2 ))

d) Z1‘=(m Z1(Z2 4 m)/(1-m2 ))/m Z1(Z1 4 m/(1-m2 )) View Answer Answer: c Explanation: As Zoπ = Zoπ’, √(Z1Z2/(1+Z1/4 Z2))=√(((Z1‘ Z2)/m)/(1+(Z1‘)/(4 Z2/m))). On solving, Z1‘=(m Z1(Z2 4 m)/(1m2 ))/m Z1(Z2 4 m/(1-m2 )) .

5. The value of resonant frequency in the m-derived low filter is? a) fr=1/(√(LC(1+m2 ) ))

b) fr=1/(√(πLC(1+m2 ) )) c) fr=1/(√(LC(1-m2 ) ))

d) fr=1/(√(πLC(1-m2 ) )) View Answer Answer: d

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Explanation: ωr2 = 1/(LC(1-m2)). So the value of resonant frequency in the m-derived low filter is fr=1/√(πLC(1m2 ) ).

6. The cut-off frequency of the low filter is? a) 1/√LC b) 1/(π√LC) c) 1/√L d) 1/(π√L) View Answer Answer: b Explanation: To determine the cut-off frequency of the low filter we place m = 0. So fc=1/(π√LC). 7. The resonant frequency of m-derived low filter in of the cut-off frequency of low filter is? a) fc/√(1-m2 )

b) fc/√(1+m2 )

c) fc/(π√(1-m2 ))

d) fc/(π√(1+m2 )) View Answer Answer: a Explanation: If a sharp cut-off is desired, the frequency at infinity should be near to fc. The resonant frequency of m-derived low filter in of the cut-off frequency of low filter is fr=fc/√(1-m2). 8. The expression of m of the m-derived low filter is? a) m=√(1+(fc/fr)2 ) b) m=√(1+(fc/f)2)

c) m=√(1-(fc/fr)2 ) 4 of 6

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d) m=√(1-(fc/f)2 ) View Answer Answer: c Explanation: As fr=fc/√(1-m2). The expression of m of the m-derived low filter is m=√(1-(fc/fr)2 ).

9. Given a m-derived low filter has cut-off frequency 1 kHz, design impedance of 400Ω and the resonant frequency of 1100 Hz. Find the value of k. a) 400 b) 1000 c) 1100 d) 2100 View Answer Answer: a Explanation: The value of k is equal to the design impedance. Given design impedance is 400Ω. So, k = 400. 10. The value of m from the information provided in question 9. a) 0.216 b) 0.316 c) 0.416 d) 0.516 View Answer Answer: c Explanation: m=√(1-(fc/fr)2) fc = 1000, fr = 1100. On substituting m=√(1-(1000/1100)2 )=0.416.

Sanfoundry Global Education & Learning Series –

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Network Theory. To practice all areas of Network Theory, here is complete set of 1000+ Multiple Choice Questions and Answers.

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Attenuators - Network Theory Questions and A...


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Attenuators - Network Theory Questions and Answers by Manish 4-5 minutes

This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “Attenuators”. 1. The attenuation in dB in of input power (P1) and output power (P2) is? a) log10 (P1/P2) b)10 log10 (P1/P2) c) log10 (P2/P1) d) 10 log10 (P2/P1) View Answer Answer: b Explanation: The increase or decrease in power due to insertion or substitution of a new element in a network can be conveniently expressed in decibels or in nepers. The attenuation in dB in of input power (P1) and output power (P2) is Attenuation in dB = 10 log10 (P1/P2). 2. If V1 is the voltage at port 1 and V2 is the voltage at port 2, then the attenuation in dB is? a) 20 log10 (V1/V2)

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b) 10 log10 (V1/V2) c) 20 log10 (V2/V1) d) 10 log10 (V2/V1) View Answer Answer: a Explanation: If V1 is the voltage at port 1 and V2 is the voltage at port 2, then the attenuation in dB is Attenuation in dB =20 log10 (V1/V2) where V1 is the voltage at port 1 and V2 is the voltage at port 2. 3. What is the attenuation in dB assuming I1 is the input current and I2 is the output current leaving the port? a) 10 log10 (I1/I2) b) 10 log10 (I2/I1) c) 20 log10 (I2/I1) d) 20 log10 (I1/I2) View Answer Answer: d Explanation: Assuming I1 is the input current and I2 is the output current leaving the port, the attenuation in dB is Attenuation in dB =20 log10 (I1/I2) where I1 is the input current and I2 is the output current leaving the port. 4. The value of one decibel is equal to? a) log10 (N) b) 10 log10 (N) c) 20 log10 (N) d) 40 log10 (N) View Answer Answer: c 2 of 5

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Explanation: The value of one decibel is equal to 20 log10 (N). One decibel = 20 log10 (N) where N is the attenuation. 5. The value of N in dB is? a) N= anti log (dB) b) N= anti log(dB/10) c) N=anti log(dB/20) d) N=anti log(dB/40) View Answer Answer: c Explanation: The value of N in dB can be expressed as N=anti log(dB/20). 6. In the circuit shown below, find the value of I1/I2.

a) (R1-R2+R0)/R2 b) (R1+R2+R0)/R2 c) (R1-R2-R0)/R2 d) (R1+R2-R0)/R2 View Answer Answer: b Explanation: R2(I1-I2)=I2(R1+R0) => I2(R2+R1+R0)I1R2. On solving, I1/I2=(R1+R2+R1)/R2. 7. Determine the value of N in the circuit shown in question 6. a) (R1+R2-R0)/R2

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b) (R1-R2-R0)/R2 c) (R1+R2+R0)/R2 d) (R1-R2+R0)/R2 View Answer Answer: c Explanation: N = I1/I2. We got I1/I2=(R1+R2+R1)/R2. So on substituting we get N = (R1+R2+R0)/R2. 8. The value of the characteristic impedance R0 in of R1 and R2 and R0 in the circuit shown in question 6 is? a) R1+R2(R1+R0)/(R1+R0+R2) b) R1+ R2(R1+R0)/(R1+R0+R2) c) R2+ R2(R1+R0)/(R1+R0+R2) d) R0+R2(R1+R2)/(R1+R0+R2) View Answer Answer: b Explanation: The value of the characteristic impedance R0 in of R1 and R2 and R0 when it is terminated in a load of R0 is R0=R1+ R2(R1+R0)/(R1+R0+R2). 9. Determine the value of R1 in of R0 and N in the circuit shown in question 6 is? a) R1= R0(N-1)/(N+1) b) R1= R0(N+1)/(N+1) c) R1= R0(N-1)/(N-1) d) R1= R0(N+1)/(N-1) View Answer Answer: a Explanation: R0 = R1+(R1+R0)/N. On solving, the value of R1 in of R0 and N is R1= R0(N-1)/(N+1). 4 of 5

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10. Determine the value of R2 in of R0 and N in the circuit shown in question 6 is? a) R2= NR0/(N2-1)

b) R2= 2 NR0/(N2-1) c) R2= 3 NR0/(N2-1)

d) R2= 4 NR0/(N2-1) View Answer Answer: b Explanation: NR2 = R1+R0+R2. On substituting the value of R1, we get the value of R2 in of R0 and N as R2= 2 NR0/(N2-1).

Sanfoundry Global Education & Learning Series – Network Theory. To practice all areas of Network Theory, here is complete set of 1000+ Multiple Choice Questions and Answers.

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Inverse Network Questions and Answers


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Inverse Network Questions and Answers by Manish 4-5 minutes

This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “Inverse Network”. 1. The impedances Z1 and Z2are said to be inverse if? a) Z1Z2 = R0 b) Z1 + Z2 = R0 c) 1/Z1+1/Z2=R0 d) Z1Z2 = R02 View Answer Answer: d Explanation: The impedances Z1 and Z2 are said to be inverse if the geometric mean of the two impedances is a real number. 2. An inverse network may be obtained by? a) Converting each series branch into another series branch b) Converting each series branch into another parallel branch c) Converting each parallel branch into another series branch

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d) None of the mentioned View Answer Answer: c Explanation: An inverse network may be obtained by converting each parallel branch into another series branch and vice-versa and not by converting each series branch into another series branch and not by converting each series branch into another parallel branch. 3. An inverse network may be obtained by converting each resistance element R into a corresponding resistive element of value? a) R02/R

b) R/R02 c) R0/R d) R/R0 View Answer Answer: a Explanation: To obtain the inverse network we have to convert each resistance element R into a corresponding resistive element of value R02/R. 4. An inverse network may be obtained by converting each inductance L into a capacitance of value? a) L/R0

b) L/R02 c) R0/L

d) R02/L View Answer Answer: b 2 of 6

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Explanation: An inverse network may be obtained by converting Each inductance L should be converted into a capacitance of value L/R02 to obtain the inverse network. 5. An inverse network may be obtained by converting each capacitance C into an inductance of value? a) CR02 b) CR0

c) R02/C

d) C/R02 View Answer Answer: a Explanation: An inverse network is obtained by converting each capacitance C into an inductance of value CR02 where R0 is resistance. 6. Consider the network shown below. Find the value of capacitance C1‘ after converting the inductance L1 into a capacitance.

a) R02/L1 b) R0/L1

c) L1/R02 d) L1/R0 View Answer 3 of 6

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Answer: c Explanation: An inverse network may be obtained by converting Each inductance L should be converted into a capacitance of value L/R02 to obtain the inverse network. The value of capacitance C1‘ after converting the

inductance into a capacitance is L1/R02. C1’ = L1/R02. 7. In the network showed in question 6, find the value of inductance L1‘ after converting the capacitance into an inductance. a) C1/R02 b) R02/C1 c) C1R0

d) C1R02 View Answer Answer: d Explanation: An inverse network is obtained by converting each capacitance C into an inductance of value CR02

where R0 is resistance. The value of inductance L1‘ after converting the capacitance into an inductance is L1‘ = C1R02.

8. From the network showed in question 6, find the value of resistance R1‘ after converting the resistance R1. a) R1/R0 b) R0/R1

c) R1/R02

d) R02/R1 View Answer Answer: d 4 of 6

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Explanation: To obtain the inverse network we have to convert each resistance element R into a corresponding resistive element of value R02/R. The value of resistance R1‘ after converting R1 is R1‘ = R02/R1.

9. The value of the capacitance C2‘ after converting the

inductor into the C2‘ in the network showed in question 6. a) L2/R02 b) L2/R0

c) R02/L2 d) R0/L2 View Answer Answer: a Explanation: An inverse network may be obtained by converting Each inductance L should be converted into a capacitance of value L/R02 to obtain the inverse network. The value of the capacitance C2‘ after converting the inductor into the capacitance is C2‘ = L2/R02. 10. The value of the inductor L2‘ after converting the

capacitor into the L2‘ in the network showed in question 6. a) R02/C2 b) C2R02 c) C2R0

d) R02/C2 View Answer Answer: b Explanation: An inverse network is obtained by converting each capacitance C into an inductance of value CR02 5 of 6

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where R0 is resistance. The value of the inductor L2‘ after

converting the capacitor into the inductance is L2‘ = C2R02. Sanfoundry Global Education & Learning Series – Network Theory. To practice all areas of Network Theory, here is complete set of 1000+ Multiple Choice Questions and Answers.

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Series Equalizer - Network Theory Questions a...


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Series Equalizer - Network Theory Questions and Answers by Manish 4-5 minutes

This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “Series Equalizer”. 1. The value of attenuation D is equal to? a) log10 (N) b) 10 log10 (N) c) 20 log10 (N) d) 40 log10 (N) View Answer Answer: a Explanation: The value of attenuation D is equal to log10 (N). Attenuation D = log10 (N) where N is input to output power ratio of the load. 2. The value of N in of attenuation D is? a) antilog(D) b) antilog(D/10) c) antilog(D/20) d) antilog(D/40) View Answer

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Answer: b Explanation: The value of N in of attenuation D is antilog(D/10). N = antilog(D/10) where D is attenuation in decibels. 3. The input to output power ratio of the load (N) is the ratio of the________ to the __________ a) Maximum power delivered to the load when the equalizer is not present, power delivered to the load when equalizer is present b) Power delivered to the load when equalizer is present, maximum power delivered to the load when the equalizer is not present c) Maximum power delivered to the load when the equalizer is present, power delivered to the load when equalizer is not present d) Power delivered to the load when equalizer is not present, maximum power delivered to the load when the equalizer is present View Answer Answer: a Explanation: The input to output power ratio of the load (N) is the ratio of the maximum power delivered to the load when the equalizer is not present to the power delivered to the load when equalizer is present. 4. The N is defined as? a) output power/ input power b) input power/ output power c) output power at inductor/ input power

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d) output power at capacitor/ input power View Answer Answer: b Explanation: The N is defined as the ratio of input power to the output power. N =Pi/Pl where Pi is input power and Pl is output power. 5. The expression of input power of a series equalizer is? a) Vmax2/Ro

b) Vmax2/2Ro c) Vmax2/3Ro

d) Vmax2/4Ro View Answer Answer: d Explanation: The expression of input power of a series equalizer is Pi=(Vmax/2Ro)2 Ro=Vmax2/4Ro. 6. The expression of current flowing in a series equalizer is? a) Vmax/√((Ro)2+(X1)2)

b) Vmax/√((2Ro)2+(X1)2 )

c) Vmax/√((2Ro)2+(2X1)2 ) d) Vmax/√((Ro)2+(2X1)2 ) View Answer Answer: c Explanation: When the equalizer is connected, the expression of current flowing in a series equalizer is I1=

Vmax/√((2Ro)2+(2X1)2 ) where Vmax is voltage applied to the network and Ro is resistance of the load as well as source and 2X1 is the reactance of the equalizer.

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7. What is the power at the load of a series equalizer? a) [ Vmax2/(Ro2+X12 )]Ro

b) [ Vmax2/(2(Ro2+X12))]Ro c) [ Vmax2/(3(Ro2+X12))]Ro

d) [ Vmax2/(4(Ro2+X12))]Ro View Answer Answer: d Explanation: The power at the load of a series equalizer is P=(Vmax/√((2Ro)2+(2X1)2 ))2 Ro =[Vmax2/(4(Ro2+X12))]Ro. 8. Determine the value of N in the series equalizer. a) 1+ X12/Ro2 b) X12/Ro2

c) 1+ Ro2/X12 d) Ro2/X12

View Answer Answer: a Explanation: The N is defined as the ratio of input power to the output power. N=Pi/Pl =(Vmax2/4Ro)/[Vmax2/(4(Ro2+X12))]Ro=1+X12/Ro2 . 9. The expression of N in a full series equalizer considering Z1 as inductor and Z2 as capacitor is? a) Ro2/(ωL1)2

b) 1+ Ro2/(ωL1)2 c) (ω2 L12)/Ro2

d) 1+ (ω2 L12)/Ro2 View Answer Answer: d

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Explanation: The expression of N in a full series equalizer considering Z1 as inductor and Z2 as capacitor is N = 1 + X12/Ro2 = 1+ (ω2 L12)/Ro2 .

10. The expression of N in a full series equalizer considering Z1 as capacitor and Z2 as inductor is? a) 1+ (ω2 L12)/Ro2 b) (ω2 L12)/Ro2

c) 1+ Ro2/(ωL1)2 d) Ro2/(ωL1)2 View Answer Answer: c Explanation: The expression of N in a full series equalizer considering Z1 as capacitor and Z2 as inductor is N = 1+ Ro2/X22 = 1+Ro2/(ωL1)2 .


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Shunt Equalizer - Network Theory Questions an...


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Shunt Equalizer - Network Theory Questions and Answers by Manish 3-4 minutes

This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “Shunt Equalizer”. 1. In the shunt equalizer, the current flowing from the source is? a) Vmax(2Ro+jX1)/2Ro(Ro+jX1) b) Vmax(Ro+jX1)/Ro(Ro+jX1) c) Vmax(Ro+jX1)/2Ro(Ro+jX1) d) Vmax(2Ro+jX1)/Ro(Ro+jX1) View Answer Answer: a Explanation: In the shunt equalizer, the current flowing from the source is Is= Vmax/(Ro+(Ro||jX1/2)). On solving, Is= Vmax(2Ro+jX1)/2Ro(Ro+jX1) . 2. What is the load current in of source current in the shunt equalizer? a) Is jX1/(Ro+jX1) b) Is jX1/(Ro+2jX1) c) Is jX1/(2Ro+2jX1)

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d) Is jX1/(2Ro+jX1) View Answer Answer: d Explanation: The load current in of source current in the shunt equalizer is Il = Is (jX1/2)/(Ro+jX1/2)). On solving, Il= Is jX1/(2Ro+jX1). 3. What is the load current in of Vmax in the shunt equalizer? a) (VmaxjX1)/(Ro(2Ro+jX1)) b) (VmaxjX1)/(2Ro(2Ro+jX1)) c) (VmaxjX1)/(2Ro(Ro+jX1)) d) (VmaxjX1)/(Ro(Ro+jX1)) View Answer Answer: c Explanation: On substituting Is in the load current equation we get the load current in of Vmax in the shunt equalizer as Il= (VmaxjX1)/(2Ro(Ro+jX1)). 4. The input power in shunt equalizer is? a) Vmax2/Ro

b) Vmax2/2Ro c) Vmax2/3Ro

d) Vmax2/4Ro View Answer Answer: d Explanation: The expression of input power of a shunt equalizer is Pi=(Vmax/2Ro)2 Ro=Vmax2/4Ro. 5. What is the power at the load of a shunt equalizer?

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a) [ (Vmax2 X12)/(Ro(Ro2+X12))]. b) [ (Vmax2 X12)/(2Ro(Ro2+X12))]. c) [ (Vmax2 X12)/(3Ro(Ro2+X12))]. d) [ (Vmax2 X12)/(4Ro(Ro2+X12))]. View Answer Answer: d Explanation: The power at the load of a series equalizer is P=((Vmax jX1)/(2Ro(Ro+jX1)))2 Ro =[(Vmax2 X12)/(4Ro(Ro2+X12))].

6. The value of N in shunt equalizer is? a) 1+ X12/Ro2 b) X12/Ro2

c) 1+ Ro2/X12 d) Ro2/X12

View Answer Answer: c Explanation: The N is defined as the ratio of input power to the output power. N=Pi/Pl=(Vmax2/4Ro)/( (Vmax2 X12)/4Ro(Ro2+X12 ) )=1+ Ro2/X12 .

7. The propagation constant of a symmetrical T-section and π-section are the same. a) True b) False View Answer Answer: a Explanation: The propagation constant of a symmetrical T-section and π-section are the same. 3 of 5

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8. The attenuation is not sharp in the stop band for an m-derived filter. a) True b) False View Answer Answer: b Explanation: The attenuation is sharp in the stop band for an m-derived filter. So the given statement is not true. 9. The bridged-T phase equalizer consists of? a) Only pure inductors b) Only pure capacitors c) Only pure resistors d) Only pure reactance View Answer Answer: d Explanation: The bridged-T phase equalizer consists of only pure reactances. So the bridged T-circuit consists of only inductive or capacitive elements not resistive elements. 10. A lattice phase equalizer is a constant equalizer which satisfies the equation? a) Z1Z2 = Ro b) Z1 + Z2 = Ro c) 1/Z1+1/Z2=Ro d) Z1Z2 = Ro2 View Answer Answer: d Explanation: The lattice phase equalizer consists of only reactive components. So a lattice phase equalizer is a 4 of 5

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constant equalizer if the following equation is satisfied. Z1Z2 = Ro2.


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